Notice: Undefined index: op

I get the error message:

*Notice*: Undefined index: op

When trying to set up a form. I have looked everywhere for the solution.
I don't understnadn how to define that index. The come it comes from is:

if ($_POST['op'] != 'ds') {
$display_block = "

Re: Notice: Undefined index: op

> if ($_POST['op'] != 'ds') {
> $display_block = "
>

Re: Notice: Undefined index: op

On Tue, 22 Feb 2005 10:47:43 -0600, Matt M. wrote:
> > if ($_POST['op'] != 'ds') {
> > $display_block = "
> >

Re: Notice: Undefined index: op

Notices have been turned on your PHP installation. This means you will
need to declare all of your variables otherwise you will receive a
notice. To fix your problem simply declare your POST variable before
use.

if(isset($_POST['op'])) {
$op = $_POST['op'];
} else {
$op = "";
}

if($op != 'ds') {
etc.......

> I get the error message:
>
> *Notice*: Undefined index: op
>
> When trying to set up a form. I have looked everywhere for the
> solution. I don't understnadn how to define that index. The come it
> comes from is:
>
> if ($_POST['op'] != 'ds') {
> $display_block = "
>

Re: Notice: Undefined index: op

J. Connolly wrote:
> I get the error message:
>
> *Notice*: Undefined index: op
>
> When trying to set up a form. I have looked everywhere for the solution.
> I don't understnadn how to define that index. The come it comes from is:
>
> if ($_POST['op'] != 'ds') {
> $display_block = "
>

Re: Notice: Undefined index: op

Thank you everyone for your help. None of the solutions helped though.
It is a long story, I have to use the undefined 'op' in a few places and
all f the solution end up causing other error. But I appreciate the help
and I understand when the problem is alot clearer.. I just turned off
the error reporting like everyone suggested. Maybe when I learn a bit
more I can go back and fix it. My application runs fine, I just like
everything to be 'perfect'.
jzf



Martin Norland wrote:

> J. Connolly wrote:
>
>> I get the error message:
>>
>> *Notice*: Undefined index: op
>>
>> When trying to set up a form. I have looked everywhere for the
>> solution. I don't understnadn how to define that index. The come it
>> comes from is:
>>
>> if ($_POST['op'] != 'ds') {
>> $display_block = "
>>
>> Your E-mail Address:
>>
>> >> checked/>subscribe

>> unsubscribe
>>
>>
>> ";
>> }
>>
>> I am trying to create a form which allows my users to join a mailing
>> list. I conceptually understand what the problem is but cannot find
>> out how to solve the problem. I cannot find out how to define 'op'.
>> Please do not tell me to lower my error reporting levels. I would
>> rather fix the problems. Thank you,
>> Joseph
>
> $_POST is likely empty, because the user requesting the page has
> likely not submitted the form (yet). What you probably want (since
> you aren't going to lower the error reporting levels) is:
>
> if ( isset($_POST['op']) && $_POST['op'] == 'ds' ) {
> // do your operation here
> } else {
> // print your form/etc. here
> }
>
> You may want to use a different quoting style - I can't recall the
> name, but it's taken from perl
>
> echo << >

Re: Notice: Undefined index: op

On Tue, 2005-02-22 at 10:49, Matt M. wrote:
> On Tue, 22 Feb 2005 10:47:43 -0600, Matt M. wrote:
> > > if ($_POST['op'] != 'ds') {
> > > $display_block = "
> > >
> > > Your E-mail Address:
> > >
> > > subscribe

> > > unsubscribe
> > >
> > >
> > > ";
> > > }
> >
> > try:
> >
> > if (isset($_POST['op']) && $_POST['op'] != 'ds')
> >
>
> sorry for 2 emails, looks like you would want
> if (!isset($_POST['op']) || $_POST['op'] != 'ds')
>

I vote for the first one.

Bret

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Re: Notice: Undefined index: op

Bret Hughes wrote:
> On Tue, 2005-02-22 at 10:49, Matt M. wrote:
>
>>On Tue, 22 Feb 2005 10:47:43 -0600, Matt M. wrote:
[snip]
>>>try:
>>>
>>>if (isset($_POST['op']) && $_POST['op'] != 'ds')
>>>
>>
>>sorry for 2 emails, looks like you would want
>>if (!isset($_POST['op']) || $_POST['op'] != 'ds')
>>
>
> I vote for the first one.
>
> Bret

Your vote is misplaced - the first one isn't what he wanted... with that
statement, his form will never be printed and it can never be set.

Cheers,
--
- Martin Norland, Sys Admin / Database / Web Developer, International
Outreach x3257
The opinion(s) contained within this email do not necessarily represent
those of St. Jude Children's Research Hospital.

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Re: Notice: Undefined index: op

if you conisder passing the $_POST['op'] to a var called $op, then you could
define the var $op as an empty string

$op ="";


Bastien

>From: "J. Connolly"
>To: PHP list
>Subject: Re: [PHP-DB] Notice: Undefined index: op
>Date: Tue, 22 Feb 2005 12:20:06 -0500
>
>Thank you everyone for your help. None of the solutions helped though. It
>is a long story, I have to use the undefined 'op' in a few places and all f
>the solution end up causing other error. But I appreciate the help and I
>understand when the problem is alot clearer.. I just turned off the error
>reporting like everyone suggested. Maybe when I learn a bit more I can go
>back and fix it. My application runs fine, I just like everything to be
>'perfect'.
>jzf
>
>
>
>Martin Norland wrote:
>
>>J. Connolly wrote:
>>
>>>I get the error message:
>>>
>>>*Notice*: Undefined index: op
>>>
>>>When trying to set up a form. I have looked everywhere for the solution.
>>>I don't understnadn how to define that index. The come it comes from is:
>>>
>>>if ($_POST['op'] != 'ds') {
>>> $display_block = "
>>>

Re: Notice: Undefined index: op

On Tue, 2005-02-22 at 11:31, Martin Norland wrote:
> Bret Hughes wrote:
> > On Tue, 2005-02-22 at 10:49, Matt M. wrote:
> >
> >>On Tue, 22 Feb 2005 10:47:43 -0600, Matt M. wrote:
> [snip]
> >>>try:
> >>>
> >>>if (isset($_POST['op']) && $_POST['op'] != 'ds')
> >>>
> >>
> >>sorry for 2 emails, looks like you would want
> >>if (!isset($_POST['op']) || $_POST['op'] != 'ds')
> >>
> >
> > I vote for the first one.
> >
> > Bret
>
> Your vote is misplaced - the first one isn't what he wanted... with that
> statement, his form will never be printed and it can never be set.
>

You are right of course, In looking at the original post I misread it
to be if (! $_POST['op'] != 'ds ). I guess Since this is the sort of
construct I have cleaned up the most lately. Actually most of what I
have been finding is stuff like if (!$varname ){
That is, doing something if a variable is not set to a true value and
also using that for a test for existence.

turn on notices and get a lesson on how to make a log file grow quickly
:)

Bret

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Re: Notice: Undefined index: op

Martin Norland wrote:
> J. Connolly wrote:
>

....

> You may want to use a different quoting style - I can't recall the name,
> but it's taken from perl

HEREDOC. (i believe its custom to write it in capitals,)

>
> echo << >
> ...
> the rest of your stuff, then on its own line right at the beginning of
> the line (no tabs/etc. :( )
> ...
> EOF;
>
> it basically echo's until it sees that delimiter, that could be EOD or
> STOP or whatever (well, there might be reserved words issues - I could
> more easily check if I could remember the name of the quoting style...)
>
> Cheers

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