help in reg. exp.

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Hi All,

=20

I have string like OMS.FD.08.03.000.0 Now my req. is that if the string
contains .0 at the end then I want to remove that .0 but if any other
digit is there other than .0 then don't do anything.

=20

For example: if string is : OMS.FD.08.03.000.0 then regular expression
should give OMS.FD.08.03.000

=20

But if string is : OMS.FD.08.03.000.18 then don't do anything=20

=20

Please help.

=20

Regards,

Irfan

=20


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Re: help in reg. exp.

On Mon, Apr 21, 2008 at 7:17 AM, wrote:
snip
> I have string like OMS.FD.08.03.000.0 Now my req. is that if the string
> contains .0 at the end then I want to remove that .0 but if any other
> digit is there other than .0 then don't do anything.
snip

What have you tried so far? You might consider reading the following
documentation on how regexes and substitutions work (hint: this is an
incredibly simple substitution):

perldoc perlretut
perldoc perlrequick
perldoc perlre
perldoc perlop

or

http://perldoc.perl.org/perlretut.html
http://perldoc.perl.org/perlrequick.html
http://perldoc.perl.org/perlre.html
http://perldoc.perl.org/perlop.html

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Chas. Owens
wonkden.net
The most important skill a programmer can have is the ability to read.

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Re: help in reg. exp.

On Mon, Apr 21, 2008 at 7:17 PM, wrote:
> Hi All,
>
>
>
> I have string like OMS.FD.08.03.000.0 Now my req. is that if the string
> contains .0 at the end then I want to remove that .0 but if any other
> digit is there other than .0 then don't do anything.
>
>
>
> For example: if string is : OMS.FD.08.03.000.0 then regular expression
> should give OMS.FD.08.03.000
>

try:

$str =~ s/\.0$//;


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Re: help in reg. exp.

Irfan.Sayed@t-systems.com wrote:
>
> I have string like OMS.FD.08.03.000.0 Now my req. is that if the string
> contains .0 at the end then I want to remove that .0 but if any other
> digit is there other than .0 then don't do anything.
>
> For example: if string is : OMS.FD.08.03.000.0 then regular expression
> should give OMS.FD.08.03.000
>
> But if string is : OMS.FD.08.03.000.18 then don't do anything

sub remdotzero {
my $str = shift;
$str =~ /(.*?)(?:\.0)?$/;
return $1
}



Rob

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