Re: Ordinal number within a table

[Sorry for cross-posting.]

This is in continuation with the above mentioned subject - I am trying =
to find the 'display data order' for the returned resultset. The =
following thread very well answers my question:

http://lists.mysql.com/mysql/185626

a) SET @row=3D0;
b) SELECT (@row:=3D@row+1) AS row, ename, empno FROM emp ORDER BY empno;

+-----+--------+-------+
| row | ename | empno |
+-----+--------+-------+
| 1 | SMITH | 7369 |
| 2 | ALLEN | 7499 |
| 3 | WARD | 7521 |
| 4 | JONES | 7566 |
| 5 | MARTIN | 7654 |
+-----+--------+-------+

However, I am trying to use it in a perl script instead of from command =
line, and I am not sure how exactly to do it. I need to execute both =
statements a & b together or else I get

+-----+--------+-------+
| row | ename | empno |
+-----+--------+-------+
|NULL | SMITH | 7369 |
|NULL | ALLEN | 7499 |
|NULL | WARD | 7521 |
|NULL | JONES | 7566 |
|NULL | MARTIN | 7654 |
+-----+--------+-------+

How can I execute both (a) and (b) in my perl script?

Thanks for any help.
Nishi


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