selective replacements

am 12.11.2005 09:33:05 von meltedown

I have this in one of my php scripts to take out line breaks:
$html=str_replace(array("\n","\r"),"",$html);

Now I would like to leave some line breaks.
For example, if $html has something like this:
" default text\n with line \nbreaks "
I would like to leave all the linebreaks between the tags. Does any one know of a regular expression that can do this ? </article> <article> <h2>Re: selective replacements</h2>am 12.11.2005 17:18:10 von Matt Garrish "meltedown" <groups2@reenie.org> wrote in message news:5Nhdf.12304$Ur3.9768@fe01.news.easynews.com... >I have this in one of my php scripts to take out line breaks: > $html=str_replace(array("\n","\r"),"",$html); > > Now I would like to leave some line breaks. > For example, if $html has something like this: > "<textarea> default text\n with line \nbreaks "
> I would like to leave all the linebreaks between the tags. > Does any one know of a regular expression that can do this ? alt.php is down the hall... Matt </article> <article> <h2>Re: selective replacements</h2>am 12.11.2005 19:10:53 von meltedown Matt Garrish wrote: > "meltedown" <groups2@reenie.org> wrote in message > news:5Nhdf.12304$Ur3.9768@fe01.news.easynews.com... > >>I have this in one of my php scripts to take out line breaks: >> $html=str_replace(array("\n","\r"),"",$html); >> >>Now I would like to leave some line breaks. >>For example, if $html has something like this: >>"<textarea> default text\n with line \nbreaks "
>>I would like to leave all the linebreaks between the tags. >>Does any one know of a regular expression that can do this ? > > > alt.php is down the hall... > > Matt > > Don't be nervous just because I mentioned PHP. I'm looking for a regular expression, and if its in a perl context, that's fine. I can just as easily use it in PHP. Perhaps you don't know this, but the syntax of regular expressions in PHP is almost identical to that of perl. The people in this newgroup are much much better at regular expressions than the people in the PHP group, and they do not have an answer to this question. I've already tried. How do I replace all the line breaks in a string with '', except the line breaks between <textarea> tags ? There's nothing unperl about that question. </article> <article> <h2>Re: selective replacements</h2>am 12.11.2005 20:12:14 von Matt Garrish "meltedown" <groups2@reenie.org> wrote in message news:Neqdf.19659$Ww6.10326@fe05.news.easynews.com... > Matt Garrish wrote: >> "meltedown" <groups2@reenie.org> wrote in message >> news:5Nhdf.12304$Ur3.9768@fe01.news.easynews.com... >> >>>I have this in one of my php scripts to take out line breaks: >>> $html=str_replace(array("\n","\r"),"",$html); >>> >>>Now I would like to leave some line breaks. >>>For example, if $html has something like this: >>>"<textarea> default text\n with line \nbreaks "
>>>I would like to leave all the linebreaks between the tags. >>>Does any one know of a regular expression that can do this ? >> >> >> alt.php is down the hall... >> > > Don't be nervous just because I mentioned PHP. I'm looking for a regular > expression, and if its in a perl context, that's fine. I can just as > easily use it in PHP. Perhaps you don't know this, but the syntax of > regular expressions in PHP is almost identical to that of perl. The people > in this newgroup are much much better at regular expressions than the > people in the PHP group, and they do not have an answer to this question. > I've already tried. > > How do I replace all the line breaks in a string with '', except the line > breaks between <textarea> tags ? There's nothing unperl about that > question. The reason I refused to answer has nothing to do with anything you note above, but that you should be using a parser and not a regular expression (and for that you should be using the functionality provided by PHP and not asking for help in a Perl group). The following is hack that will do what you want, but hopefully will give you an idea about why you need to do more than write a simple regular expression. (watch for wrapping on the regex) my $string = <<STR; php is no perl <textarea>for reasons that are too complicated to explain here
but you're free to google
them for yourself
STR

my $done;
$string =~ s#(.*?)(]*>.*?)?#my $txtarea=$2;(my $text
= $1)=~s/\n//;$done .="$text$txtarea"#gise;
print $done;

If you can't see why it's an abuse of the /e modifier then I wish you all
the luck in your programming future!

Matt

Re: selective replacements

am 12.11.2005 22:36:54 von meltedown

Matt Garrish wrote:
> "meltedown" wrote in message
> news:Neqdf.19659$Ww6.10326@fe05.news.easynews.com...
>
>>Matt Garrish wrote:
>>
>>>"meltedown" wrote in message
>>>news:5Nhdf.12304$Ur3.9768@fe01.news.easynews.com...
>>>
>>>
>>>>I have this in one of my php scripts to take out line breaks:
>>>> $html=str_replace(array("\n","\r"),"",$html);
>>>>
>>>>Now I would like to leave some line breaks.
>>>>For example, if $html has something like this:
>>>>" default text\n with line \nbreaks "
>>>>I would like to leave all the linebreaks between the tags. >>>>Does any one know of a regular expression that can do this ? >>> >>> >>>alt.php is down the hall... >>> >> >>Don't be nervous just because I mentioned PHP. I'm looking for a regular >>expression, and if its in a perl context, that's fine. I can just as >>easily use it in PHP. Perhaps you don't know this, but the syntax of >>regular expressions in PHP is almost identical to that of perl. The people >>in this newgroup are much much better at regular expressions than the >>people in the PHP group, and they do not have an answer to this question. >>I've already tried. >> >>How do I replace all the line breaks in a string with '', except the line >>breaks between <textarea> tags ? There's nothing unperl about that >>question. > > > The reason I refused to answer has nothing to do with anything you note > above, but that you should be using a parser and not a regular expression > (and for that you should be using the functionality provided by PHP and not > asking for help in a Perl group). > The following is hack that will do what > you want, but hopefully will give you an idea about why you need to do more > than write a simple regular expression. (watch for wrapping on the regex) > > my $string = <<STR; > php is no perl > <textarea>for reasons > that are too complicated > to explain here
> but you're free to google
> them for yourself
> STR
>
> my $done;
> $string =~ s#(.*?)(]*>.*?)?#my $txtarea=$2;(my $text
> = $1)=~s/\n//;$done .="$text$txtarea"#gise;
> print $done;
>

Thanks, but isn't there supposed to be a semi colon after
$string =~ s#(.*?)(]*>.*?)?#

Is that a typo or is that supposed to be like that ?
I'm just trying to make sure I understand it right.

> If you can't see why it's an abuse of the /e modifier then I wish you all
> the luck in your programming future!
>
> Matt
>
>

Re: selective replacements

am 12.11.2005 23:40:14 von Matt Garrish

"meltedown" wrote in message
news:Wftdf.30220$xl1.27689@fe03.news.easynews.com...
> Matt Garrish wrote:
>> "meltedown" wrote in message
>> news:Neqdf.19659$Ww6.10326@fe05.news.easynews.com...
>>
>>>Matt Garrish wrote:
>>>
>>>>"meltedown" wrote in message
>>>>news:5Nhdf.12304$Ur3.9768@fe01.news.easynews.com...
>>>>
>>>>
>>>>>I have this in one of my php scripts to take out line breaks:
>>>>> $html=str_replace(array("\n","\r"),"",$html);
>>>>>
>>>>>Now I would like to leave some line breaks.
>>>>>For example, if $html has something like this:
>>>>>" default text\n with line \nbreaks "
>>>>>I would like to leave all the linebreaks between the tags. >>>>>Does any one know of a regular expression that can do this ? >>>> >>>> >>>>alt.php is down the hall... >>>> >>> >>>Don't be nervous just because I mentioned PHP. I'm looking for a regular >>>expression, and if its in a perl context, that's fine. I can just as >>>easily use it in PHP. Perhaps you don't know this, but the syntax of >>>regular expressions in PHP is almost identical to that of perl. The >>>people in this newgroup are much much better at regular expressions than >>>the people in the PHP group, and they do not have an answer to this >>>question. I've already tried. >>> >>>How do I replace all the line breaks in a string with '', except the >>>line breaks between <textarea> tags ? There's nothing unperl about that >>>question. >> >> >> The reason I refused to answer has nothing to do with anything you note >> above, but that you should be using a parser and not a regular expression >> (and for that you should be using the functionality provided by PHP and >> not asking for help in a Perl group). > >> The following is hack that will do what you want, but hopefully will give >> you an idea about why you need to do more than write a simple regular >> expression. (watch for wrapping on the regex) >> >> my $string = <<STR; >> php is no perl >> <textarea>for reasons >> that are too complicated >> to explain here
>> but you're free to google
>> them for yourself
>> STR
>>
>> my $done;
>> $string =~ s#(.*?)(]*>.*?)?#my $txtarea=$2;(my
>> $text = $1)=~s/\n//;$done .="$text$txtarea"#gise;
>> print $done;
>>
>
> Thanks, but isn't there supposed to be a semi colon after
> $string =~ s#(.*?)(]*>.*?)?#
>
> Is that a typo or is that supposed to be like that ?
> I'm just trying to make sure I understand it right.
>

No. Look up the /e switch in perlre.

Matt

Re: selective replacements

am 13.11.2005 07:39:18 von meltedown

Matt Garrish wrote:
> "meltedown" wrote in message
> news:Wftdf.30220$xl1.27689@fe03.news.easynews.com...
>
>>Matt Garrish wrote:
>>
>>>"meltedown" wrote in message
>>>news:Neqdf.19659$Ww6.10326@fe05.news.easynews.com...
>>>
>>>
>>>>Matt Garrish wrote:
>>>>
>>>>
>>>>>"meltedown" wrote in message
>>>>>news:5Nhdf.12304$Ur3.9768@fe01.news.easynews.com...
>>>>>
>>>>>
>>>>>
>>>>>>I have this in one of my php scripts to take out line breaks:
>>>>>>$html=str_replace(array("\n","\r"),"",$html);
>>>>>>
>>>>>>Now I would like to leave some line breaks.
>>>>>>For example, if $html has something like this:
>>>>>>" default text\n with line \nbreaks "
>>>>>>I would like to leave all the linebreaks between the tags. >>>>>>Does any one know of a regular expression that can do this ? >>>>> >>>>> >>>>>alt.php is down the hall... >>>>> >>>> >>>>Don't be nervous just because I mentioned PHP. I'm looking for a regular >>>>expression, and if its in a perl context, that's fine. I can just as >>>>easily use it in PHP. Perhaps you don't know this, but the syntax of >>>>regular expressions in PHP is almost identical to that of perl. The >>>>people in this newgroup are much much better at regular expressions than >>>>the people in the PHP group, and they do not have an answer to this >>>>question. I've already tried. >>>> >>>>How do I replace all the line breaks in a string with '', except the >>>>line breaks between <textarea> tags ? There's nothing unperl about that >>>>question. >>> >>> >>>The reason I refused to answer has nothing to do with anything you note >>>above, but that you should be using a parser and not a regular expression >>>(and for that you should be using the functionality provided by PHP and >>>not asking for help in a Perl group). >> >>>The following is hack that will do what you want, but hopefully will give >>>you an idea about why you need to do more than write a simple regular >>>expression. (watch for wrapping on the regex) >>> >>>my $string = <<STR; >>>php is no perl >>><textarea>for reasons >>>that are too complicated >>>to explain here
>>>but you're free to google
>>>them for yourself
>>>STR
>>>
>>>my $done;
>>>$string =~ s#(.*?)(]*>.*?)?#my $txtarea=$2;(my
>>>$text = $1)=~s/\n//;$done .="$text$txtarea"#gise;
>>>print $done;
>>>
>>
>>Thanks, but isn't there supposed to be a semi colon after
>>$string =~ s#(.*?)(]*>.*?)?#
>>
>>Is that a typo or is that supposed to be like that ?
>>I'm just trying to make sure I understand it right.
>>
>
>
> No. Look up the /e switch in perlre.
>
> Matt
>
>
Ok. Thanks for clarifying. You've given me an idea by suggesting a
parser. I do have my own html parser and I think I can adjust it so
instead of just taking out all the linebreaks, it takes them out on a
tag by tag basis.

Re: selective replacements

am 18.11.2005 21:44:35 von Jim Gibson

In article , meltedown
wrote:

> Matt Garrish wrote:
> > "meltedown" wrote in message
> > news:Neqdf.19659$Ww6.10326@fe05.news.easynews.com...
> >

[problem description snipped]

> > The following is hack that will do what
> > you want, but hopefully will give you an idea about why you need to do more
> > than write a simple regular expression. (watch for wrapping on the regex)
> >
> > my $string = < > > php is no perl
> > for reasons > > that are too complicated > > to explain here
> > but you're free to google
> > them for yourself
> > STR
> >
> > my $done;
> > $string =~ s#(.*?)(]*>.*?)?#my $txtarea=$2;(my $text
> > = $1)=~s/\n//;$done .="$text$txtarea"#gise;
> > print $done;
> >
>
> Thanks, but isn't there supposed to be a semi colon after
> $string =~ s#(.*?)(]*>.*?)?#
>

No. The s#...# is the first part of the substitution operator, written
by Matt to use # as a delimiter: s#...#...#gise;
The entire statement is in two lines:

$string =~ s#...#...
....#gise;

> Is that a typo or is that supposed to be like that ?
> I'm just trying to make sure I understand it right.

Did it work when you tried it? Did you get a compile error when you
added a semicolon?

>
> > If you can't see why it's an abuse of the /e modifier then I wish you all
> > the luck in your programming future!
> >
> > Matt

I am leaving Matt's good advice in my response.

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