add_delta_days: 30.06.2006 +1 Day = 01.07.2006?

Hi,

attention, Beginner!

I'm wondering about the calculation from Modul Date::Calc.

The Code:

sub ids_tomorrow() {
my($year,$month,$day) = Add_Delta_Days(((localtime)[5,4,3]),1);
$year=$year+1900;
printf("Id's, tommorow: %02d.%02d.%04d\n",$day,$month,$year);
}

give me (called on 30.06.2006) as Resoult the Date 01.07.2006?
It should be 31.06.2006.
What made i wrong?

"Date::Calc" version 5.4
Perl: Ver. 5.8.8

Thanx for Help
Thomas

Re: add_delta_days: 30.06.2006 +1 Day = 01.07.2006?

thomas.reiss@gmx.de wrote:
> Hi,
>
> attention, Beginner!
>
> I'm wondering about the calculation from Modul Date::Calc.
>
> The Code:
>
> sub ids_tomorrow() {
> my($year,$month,$day) = Add_Delta_Days(((localtime)[5,4,3]),1);
> $year=$year+1900;
> printf("Id's, tommorow: %02d.%02d.%04d\n",$day,$month,$year);
> }
>
> give me (called on 30.06.2006) as Resoult the Date 01.07.2006?
> It should be 31.06.2006.
> What made i wrong?
>
> "Date::Calc" version 5.4
> Perl: Ver. 5.8.8
>

June only has 30 days.

Mark

Re: add_delta_days: 30.06.2006 +1 Day = 01.07.2006?

Mark Clements schrieb:

> thomas.reiss@gmx.de wrote:
> > Hi,
> >
> > attention, Beginner!
> >
> > I'm wondering about the calculation from Modul Date::Calc.
> >
> > The Code:
> >
> > sub ids_tomorrow() {
> > my($year,$month,$day) = Add_Delta_Days(((localtime)[5,4,3]),1);
> > $year=$year+1900;
> > printf("Id's, tommorow: %02d.%02d.%04d\n",$day,$month,$year);
> > }
> >
> > give me (called on 30.06.2006) as Resoult the Date 01.07.2006?
> > It should be 31.06.2006.
> > What made i wrong?
> >
> > "Date::Calc" version 5.4
> > Perl: Ver. 5.8.8
> >
>
> June only has 30 days.
>
> Mark

Upps, sorry my mistake, i live at the wrong Month ;-)
The Skript was not called on 06/2006 but on 07/2006!
But Your hint was very usefull.

localtime returns the month beginning with 0 for January,
Add_Delta_Days await the January with 1 !

so i have to add 1 to $month.

Thank's for help
Thomas