I'm new to Perl, and I'm stumped by how do I pass an argument to a
subroutine. I have a variable, $variable1, that I want to pass to a
subroutine, say subX.
I call the routine as &subX ($variableX);
sub subX (who) {
do something with $variableX;
}
As you all know, this doesn't work. I've tried to find the answer, but I get
snowed reading the solution to the problem. How do I do it?
TIA, Herb
HerbF@earthlink.net wrote:
> I'm new to Perl, and I'm stumped by how do I pass an argument to a
> subroutine. I have a variable, $variable1, that I want to pass to a
> subroutine, say subX.
>
> I call the routine as &subX ($variableX);
>
> sub subX (who) {
> do something with $variableX;
> }
subX( $variableX );
sub subX {
my $variableX = shift; # get the first argument from @_
# and store it in a lexically scoped variable
# do something with $variableX;
}
> As you all know, this doesn't work. I've tried to find the answer, but I get
> snowed reading the solution to the problem. How do I do it?
It is all explained in the Fine Manual:
perldoc perlsub
Or on the web at: http://perldoc.perl.org/perlsub.html
John
--
Perl isn't a toolbox, but a small machine shop where you can special-order
certain sorts of tools at low cost and in short order. -- Larry Wall
On 01/28/2007 01:29 PM, HerbF@earthlink.net wrote:
> I'm new to Perl, and I'm stumped by how do I pass an argument to a
> subroutine. I have a variable, $variable1, that I want to pass to a
> subroutine, say subX.
>
> I call the routine as &subX ($variableX);
>
> sub subX (who) {
> do something with $variableX;
> }
>
> As you all know, this doesn't work. I've tried to find the answer, but I get
> snowed reading the solution to the problem. How do I do it?
>
> TIA, Herb
my $variableX = 'xyz';
subX($variableX);
sub subX {
my $param = $_[0];
print "$param\n";
}
-----------------
Read the documentation:
Start->Run->"perldoc perlsub"
--
Windows Vista and your freedom in conflict:
http://www.securityfocus.com/columnists/420/2
John W. Krahn scribed:
>HerbF@earthlink.net wrote:
>> I'm new to Perl, and I'm stumped by how do I pass an argument to a
>> subroutine. I have a variable, $variable1, that I want to pass to a
>> subroutine, say subX.
>>
>> I call the routine as &subX ($variableX);
>>
>> sub subX (who) {
>> do something with $variableX;
>> }
>
>
>subX( $variableX );
>
>sub subX {
> my $variableX = shift; # get the first argument from @_
> # and store it in a lexically scoped variable
> # do something with $variableX;
>}
>
Thanks....exactly what I needed.
>
>> As you all know, this doesn't work. I've tried to find the answer, but I get
>> snowed reading the solution to the problem. How do I do it?
>
>It is all explained in the Fine Manual:
>
>perldoc perlsub
>
>Or on the web at: http://perldoc.perl.org/perlsub.html
>
If I could only understand the manual...I'm the guy they write the 'for
Dummies' books for. :-(
Herb
On Jan 28, 5:05 pm, H...@earthlink.net wrote:
> John W. Krahn scribed:
> >> As you all know, this doesn't work. I've tried to find the answer, but I get
> >> snowed reading the solution to the problem. How do I do it?
>
> >It is all explained in the Fine Manual:
>
> >perldoc perlsub
>
> >Or on the web at:http://perldoc.perl.org/perlsub.htmlIf I could only understand the manual...I'm the guy they write the 'for
> Dummies' books for. :-(
Uh-huh. It helps if you actually *read* it. Can you please explain
to me what part of the following was difficult to understand?
Any arguments passed in show up in the array @_. Therefore,
if you called a function with two arguments, those would be
stored in $_[0] and $_[1].
Paul Lalli