Variable Passing Not Sending Complete Name

I have a PHP script which simply calls another PHP script using
include(). Let's call them website.php and website_include.php, with
website.php simply including website_include.php. I can pass the
variable to website.php fine. Using an echo command, I can see that it
has the complete phrase such as "Permission Denied." When I call the
website_include.php, which is the page that actually does all the
work, the variable has changed to just "Permission." This happens with
any phrase I send. I am using the following syntax to call
website_include.php:

include("http://www.domain.com/website_include.php?variable= $phrase)

Right now, at the top of website.php and website_include.php I have a
$_GET statement to capture the variable. I have tried various
combinations of one page having it and the other not having. Having
the $_GET statement on both pages is the only way it has worked for me
so far. Any help will be greatly appreciated.

Re: Variable Passing Not Sending Complete Name

On Wed, 15 Aug 2007 15:17:47 +0200, Jerim wrote:

> I have a PHP script which simply calls another PHP script using
> include(). Let's call them website.php and website_include.php, with
> website.php simply including website_include.php. I can pass the
> variable to website.php fine. Using an echo command, I can see that it=

> has the complete phrase such as "Permission Denied." When I call the
> website_include.php, which is the page that actually does all the
> work, the variable has changed to just "Permission." This happens with=

> any phrase I send. I am using the following syntax to call
> website_include.php:
>
> include("http://www.domain.com/website_include.php?variable= 3D$phrase)=


Really try to use the local filesystem if you can, not a roundabout by =

HTTP. It's unneccessary and cumbersome in most cases.

Your problem is in this case you should have urlencoded() the $phrase, =

spaces are _not_ valid in the query string of an url.

Much easier would be:

website.php
$phrase =3D 'Test this.';
include('./website_include.php');
?>

website_include.php
echo $phrase;
?>
-- =

Rik Wasmus

Re: Variable Passing Not Sending Complete Name

On Aug 15, 8:22 am, Rik wrote:
> On Wed, 15 Aug 2007 15:17:47 +0200, Jerim wrote:
> > I have a PHP script which simply calls another PHP script using
> > include(). Let's call them website.php and website_include.php, with
> > website.php simply including website_include.php. I can pass the
> > variable to website.php fine. Using an echo command, I can see that it
> > has the complete phrase such as "Permission Denied." When I call the
> > website_include.php, which is the page that actually does all the
> > work, the variable has changed to just "Permission." This happens with
> > any phrase I send. I am using the following syntax to call
> > website_include.php:
>
> > include("http://www.domain.com/website_include.php?variable= $phrase)
>
> Really try to use the local filesystem if you can, not a roundabout by
> HTTP. It's unneccessary and cumbersome in most cases.
>
> Your problem is in this case you should have urlencoded() the $phrase,
> spaces are _not_ valid in the query string of an url.
>
> Much easier would be:
>
> website.php
> > $phrase = 'Test this.';
> include('./website_include.php');
> ?>
>
> website_include.php
> > echo $phrase;
> ?>
> --
> Rik Wasmus

I appreciate the help, but that didn't work. The variable that
website.php is sending isn't hard coded. This system is for searching
names in a database. The variable that is getting passed is a persons
name. I start out with a page that lists all names, such as name.php.
All the names are clickable, so that you can get more details on that
person. So name.php passes the persons name onto website.php.
website.php catches the variable using a $_GET statement. Then it
calls website_include.php. The full variable name between website.php
and website_include.php is getting lost. Right now actually,
website_include.php isn't showing any name. So far, the only way to
get website_include.php to show even part of the name is to pass it
the name variable in the URL, and have website_include.php do a $_GET.

Re: Variable Passing Not Sending Complete Name

On Wed, 15 Aug 2007 15:51:19 +0200, Jerim wrote:

> On Aug 15, 8:22 am, Rik wrote:
>> On Wed, 15 Aug 2007 15:17:47 +0200, Jerim wrote:
>> > I have a PHP script which simply calls another PHP script using
>> > include(). Let's call them website.php and website_include.php, wit=
h
>> > website.php simply including website_include.php. I can pass the
>> > variable to website.php fine. Using an echo command, I can see that=
it
>> > has the complete phrase such as "Permission Denied." When I call th=
e
>> > website_include.php, which is the page that actually does all the
>> > work, the variable has changed to just "Permission." This happens w=
ith
>> > any phrase I send. I am using the following syntax to call
>> > website_include.php:
>>
>> > include("http://www.domain.com/website_include.php?variable= 3D$phra=
se)
>>
>> Really try to use the local filesystem if you can, not a roundabout b=
y
>> HTTP. It's unneccessary and cumbersome in most cases.
>>
>> Your problem is in this case you should have urlencoded() the $phrase=
,
>> spaces are _not_ valid in the query string of an url.
>>
>> Much easier would be:
>>
>> website.php
>> >> $phrase =3D 'Test this.';
>> include('./website_include.php');
>> ?>
>>
>> website_include.php
>> >> echo $phrase;
>> ?>
>> --
>> Rik Wasmus

Please don't quote signatures.

> I appreciate the help, but that didn't work.

What have you tried, using the local filesystem or urlencoding your GET =
=

variable?

> The variable that
> website.php is sending isn't hard coded.

Which is irrelevant. If the variable exists in website.php be it static =
or =

dynamic, it will exist in website_include.php if you include it using th=
e =

filesystem.

> So name.php passes the persons name onto website.php.
> website.php catches the variable using a $_GET statement. Then it
> calls website_include.php.

Still using http or indeed the filesystem now?

> The full variable name between website.php
> and website_include.php is getting lost.

Which I told you was because in HTTP you have to (raw)urlencode() the =

values in the query string.
-- =

Rik Wasmus

Re: Variable Passing Not Sending Complete Name

On Aug 15, 9:00 am, Rik wrote:
> On Wed, 15 Aug 2007 15:51:19 +0200, Jerim wrote:
> > On Aug 15, 8:22 am, Rik wrote:
> >> On Wed, 15 Aug 2007 15:17:47 +0200, Jerim wrote:
> >> > I have a PHP script which simply calls another PHP script using
> >> > include(). Let's call them website.php and website_include.php, with
> >> > website.php simply including website_include.php. I can pass the
> >> > variable to website.php fine. Using an echo command, I can see that it
> >> > has the complete phrase such as "Permission Denied." When I call the
> >> > website_include.php, which is the page that actually does all the
> >> > work, the variable has changed to just "Permission." This happens with
> >> > any phrase I send. I am using the following syntax to call
> >> > website_include.php:
>
> >> > include("http://www.domain.com/website_include.php?variable= $phrase)
>
> >> Really try to use the local filesystem if you can, not a roundabout by
> >> HTTP. It's unneccessary and cumbersome in most cases.
>
> >> Your problem is in this case you should have urlencoded() the $phrase,
> >> spaces are _not_ valid in the query string of an url.
>
> >> Much easier would be:
>
> >> website.php
> >> > >> $phrase = 'Test this.';
> >> include('./website_include.php');
> >> ?>
>
> >> website_include.php
> >> > >> echo $phrase;
> >> ?>
> >> --
> >> Rik Wasmus
>
> Please don't quote signatures.
>
> > I appreciate the help, but that didn't work.
>
> What have you tried, using the local filesystem or urlencoding your GET
> variable?
>
> > The variable that
> > website.php is sending isn't hard coded.
>
> Which is irrelevant. If the variable exists in website.php be it static or
> dynamic, it will exist in website_include.php if you include it using the
> filesystem.
>
> > So name.php passes the persons name onto website.php.
> > website.php catches the variable using a $_GET statement. Then it
> > calls website_include.php.
>
> Still using http or indeed the filesystem now?
>
> > The full variable name between website.php
> > and website_include.php is getting lost.
>
> Which I told you was because in HTTP you have to (raw)urlencode() the
> values in the query string.

After playing around with it a bit, here is what you were trying to
say:

On website.php catch the variable using
$variable=rawurlencode($_GET['variable']);
Then when you call the include, pass the variable: include("http://
www.website.com/directory/website_include.php?variable=$vari able");

Re: Variable Passing Not Sending Complete Name

On Wed, 15 Aug 2007 16:24:15 +0200, Jerim wrote:
> After playing around with it a bit, here is what you were trying to
> say:
>
> On website.php catch the variable using
> $variable=3Drawurlencode($_GET['variable']);
> Then when you call the include, pass the variable: include("http://
> www.website.com/directory/website_include.php?variable=3D$va riable");

Well, preferably don't include by HTTP, but this will work.
-- =

Rik Wasmus

Re: Variable Passing Not Sending Complete Name

Jerim wrote:
> On Aug 15, 9:00 am, Rik wrote:
>> On Wed, 15 Aug 2007 15:51:19 +0200, Jerim wrote:
>>> On Aug 15, 8:22 am, Rik wrote:
>>>> On Wed, 15 Aug 2007 15:17:47 +0200, Jerim wrote:
>>>>> I have a PHP script which simply calls another PHP script using
>>>>> include(). Let's call them website.php and website_include.php, with
>>>>> website.php simply including website_include.php. I can pass the
>>>>> variable to website.php fine. Using an echo command, I can see that it
>>>>> has the complete phrase such as "Permission Denied." When I call the
>>>>> website_include.php, which is the page that actually does all the
>>>>> work, the variable has changed to just "Permission." This happens with
>>>>> any phrase I send. I am using the following syntax to call
>>>>> website_include.php:
>>>>> include("http://www.domain.com/website_include.php?variable= $phrase)
>>>> Really try to use the local filesystem if you can, not a roundabout by
>>>> HTTP. It's unneccessary and cumbersome in most cases.
>>>> Your problem is in this case you should have urlencoded() the $phrase,
>>>> spaces are _not_ valid in the query string of an url.
>>>> Much easier would be:
>>>> website.php
>>>> >>>> $phrase = 'Test this.';
>>>> include('./website_include.php');
>>>> ?>
>>>> website_include.php
>>>> >>>> echo $phrase;
>>>> ?>
>>>> --
>>>> Rik Wasmus
>> Please don't quote signatures.
>>
>>> I appreciate the help, but that didn't work.
>> What have you tried, using the local filesystem or urlencoding your GET
>> variable?
>>
>>> The variable that
>>> website.php is sending isn't hard coded.
>> Which is irrelevant. If the variable exists in website.php be it static or
>> dynamic, it will exist in website_include.php if you include it using the
>> filesystem.
>>
>>> So name.php passes the persons name onto website.php.
>>> website.php catches the variable using a $_GET statement. Then it
>>> calls website_include.php.
>> Still using http or indeed the filesystem now?
>>
>>> The full variable name between website.php
>>> and website_include.php is getting lost.
>> Which I told you was because in HTTP you have to (raw)urlencode() the
>> values in the query string.
>
> After playing around with it a bit, here is what you were trying to
> say:
>
> On website.php catch the variable using
> $variable=rawurlencode($_GET['variable']);
> Then when you call the include, pass the variable: include("http://
> www.website.com/directory/website_include.php?variable=$vari able");
>

Yes, but he's also saying if you just



the variable will be available there, also. And it's a lot faster and
easier on the server because PHP just gets the file from the filesystem
and doesn't require the webserver's involvement - like your method does.

--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attglobal.net
==================