FAQ 4.51 How do I permute N elements of a list?
am 19.09.2007 03:03:02 von PerlFAQ ServerThis is an excerpt from the latest version perlfaq4.pod, which
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4.51: How do I permute N elements of a list?
Use the "List::Permutor" module on CPAN. If the list is actually an
array, try the "Algorithm::Permute" module (also on CPAN). It's written
in XS code and is very efficient.
use Algorithm::Permute;
my @array = 'a'..'d';
my $p_iterator = Algorithm::Permute->new ( \@array );
while (my @perm = $p_iterator->next) {
print "next permutation: (@perm)\n";
}
For even faster execution, you could do:
use Algorithm::Permute;
my @array = 'a'..'d';
Algorithm::Permute::permute {
print "next permutation: (@array)\n";
} @array;
Here's a little program that generates all permutations of all the words
on each line of input. The algorithm embodied in the "permute()"
function is discussed in Volume 4 (still unpublished) of Knuth's *The
Art of Computer Programming* and will work on any list:
#!/usr/bin/perl -n
# Fischer-Krause ordered permutation generator
sub permute (&@) {
my $code = shift;
my @idx = 0..$#_;
while ( $code->(@_[@idx]) ) {
my $p = $#idx;
--$p while $idx[$p-1] > $idx[$p];
my $q = $p or return;
push @idx, reverse splice @idx, $p;
++$q while $idx[$p-1] > $idx[$q];
@idx[$p-1,$q]=@idx[$q,$p-1];
}
}
permute {print"@_\n"} split;
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