die() has access to these two:
$ perldoc -f die
the current script line number and input line number
The latter is $., but what about the former? No accessing that
from within one's program unless one wants to die() or warn()?
jidanni@jidanni.org wrote:
> die() has access to these two:
> $ perldoc -f die
> the current script line number and input line number
>
> The latter is $., but what about the former? No accessing that
> from within one's program unless one wants to die() or warn()?
Search perldata for __LINE__
John
--
Perl isn't a toolbox, but a small machine shop where you
can special-order certain sorts of tools at low cost and
in short order. -- Larry Wall
On Oct 2, 12:06 pm, jida...@jidanni.org wrote:
> die() has access to these two:
> $ perldoc -f die
> the current script line number and input line number
>
> The latter is $., but what about the former? No accessing that
> from within one's program unless one wants to die() or warn()?
Look for $0 in this perldoc
perldoc perlvar
Also read
perldoc -f caller
On Oct 2, 3:06 pm, jida...@jidanni.org wrote:
> die() has access to these two:
> $ perldoc -f die
> the current script line number and input line number
>
> The latter is $., but what about the former? No accessing that
> from within one's program unless one wants to die() or warn()?
__LINE__
see perldoc perldata (special literals)
Chris
Quoth krahnj@telus.net:
> jidanni@jidanni.org wrote:
> > die() has access to these two:
> > $ perldoc -f die
> > the current script line number and input line number
> >
> > The latter is $., but what about the former? No accessing that
> > from within one's program unless one wants to die() or warn()?
>
> Search perldata for __LINE__
Also (caller 1)[2] if you're trying to imitate die.
Ben