Why does this not work ?
$fileDir = '../folder2/';
$content is an array of php files, file1.php file2.php file3.php
etc...
$c = count($content);
for( $x=0; $x<$c; $x++ ){
include( $fileDir.$content[$x] );
}
any ideas would be appreciated,
thanks.
Xav
this seems to work,
....
for( $x=0; $x<$c; $x++ ){
include( $fileDir.'file'.($x+1).'.php' );
}
....
I don't understand why the other won't !
???
Xav
Xav schrieb:
> Why does this not work ?
> $fileDir = '../folder2/';
> $content is an array of php files, file1.php file2.php file3.php
> etc...
> $c = count($content);
> for( $x=0; $x<$c; $x++ ){
> include( $fileDir.$content[$x] );
> }
This should work if $content really contains what you expect.
var_dump($content);
I did the
...thing...
On Fri, 26 Oct 2007 13:04:58 +0200, Captain Paralytic =
> On 26 Oct, 12:01, "Rik Wasmus"
>> On Fri, 26 Oct 2007 12:47:44 +0200, Captain Paralytic
>> > Surely {$content[$x]} won't work. PHP does only one substitution so=
>> > {$content[1]} will work but {$content[$x]} doesn't (at least in my
>> > experience).
>>
>> The code:
>>
>> echo phpversion();
>> $foo =3D array(3 =3D> 'bar');
>> $x =3D 3;
>> echo "{$foo[$x]}";
>> ?>
>> Output:
>> 5.2.4bar
>>
>> The magic is in the braces.
>
> So would
> echo "$foo[$x]";
> not work then?
That's a whole other issue, and in this case it would work. See for a =
detailed explanation =
http://nl2.php.net/manual/en/language.types.string.php#langu age.types.st=
ring.parsing
Would we change it to this:
echo phpversion();
$foo =3D array(array(3 =3D> 'bar'));
$x =3D 3;
//works, outputs 'bar'
echo "{$foo[0][$x]}";
//doesn't work, outputs 'Array[3]'
echo "$foo[0][$x]"
?>
.... which is why it's a good thing to pick up the habit to use curly =
braces when using something other then a direct scalar in a string.
-- =
Rik Wasmus