How to find out what type of error it is: Failure sending mail.

This is a multi-part message in MIME format.

------=_NextPart_000_0006_01C84599.C6F99F60
Content-Type: text/plain;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable

Hi All,

How can I find the reason for such an error: Failure sending mail.

Some Code...

oMailMessage.IsBodyHtml =3D False
oMailMessage.Body =3D cEmailBody
Dim oSMTP As New SmtpClient
oSMTP.Send(oMailMessage) (in this line I am getting the above err)

Appreciate any feedback

Thanks,

Joe


------=_NextPart_000_0006_01C84599.C6F99F60
Content-Type: text/html;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable



charset=3Diso-8859-1">

Re: How to find out what type of error it is: Failure sending mail.

This is a multi-part message in MIME format.

------=_NextPart_000_0008_01C845A6.1D4DE130
Content-Type: text/plain;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable

Wrap the code in a try...catch block?


"JoeP" wrote in message =
news:%23i4RTOcRIHA.3516@TK2MSFTNGP02.phx.gbl...
Hi All,

How can I find the reason for such an error: Failure sending mail.

Some Code...

oMailMessage.IsBodyHtml =3D False
oMailMessage.Body =3D cEmailBody
Dim oSMTP As New SmtpClient
oSMTP.Send(oMailMessage) (in this line I am getting the above err)

Appreciate any feedback

Thanks,

Joe


------=_NextPart_000_0008_01C845A6.1D4DE130
Content-Type: text/html;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable



charset=3Diso-8859-1">

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com>=20
wrote in message =
href=3D"news:%23i4RTOcRIHA.3516@TK2MSFTNGP02.phx.gbl">news:% 23i4RTOcRIHA.=
3516@TK2MSFTNGP02.phx.gbl...

Hi All,

 

How can I find the reason for such an =
error:=20
Failure sending mail.

Some Code...

oMailMessage.IsBodyHtml =3D size=3D2>False
oMailMessage.Body =
cEmailBody

Dim oSMTP As New SmtpClient
color=3D#ff0000>oSMTP.Send(oMailMessage)   (in this line I =
am getting=20
the above err)

 

Appreciate any feedback

 

Thanks,

 

Joe

size=3D2> 

RE: How to find out what type of error it is: Failure sending mail.

As Scott indicated, you need to learn to wire up your code with exception
handling in order to be able to determine "what went wrong".

So at a minimum:

oMailMessage.IsBodyHtml = False
oMailMessage.Body = cEmailBody
Dim oSMTP As New SmtpClient

Begin Try
oSMTP.Send(oMailMessage) (in this line I am getting the above err)
Catch ex as Exception
System.Diagnostics.Debug.WriteLine(ex.ToString() )
End Try

Sorry, I really haven't used Visual Basic for a very long time (a good thing)
But you get the idea. Put a breakpoint on the Debug.WriteLine statement and
you can examine the exception by hovering your mouse over the "ex" variable.


-- Peter
Site: http://www.eggheadcafe.com
UnBlog: http://petesbloggerama.blogspot.com
MetaFinder: http://www.blogmetafinder.com


"JoeP" wrote:

> Hi All,
>
> How can I find the reason for such an error: Failure sending mail.
>
> Some Code...
>
> oMailMessage.IsBodyHtml = False
> oMailMessage.Body = cEmailBody
> Dim oSMTP As New SmtpClient
> oSMTP.Send(oMailMessage) (in this line I am getting the above err)
>
> Appreciate any feedback
>
> Thanks,
>
> Joe
>
>

Re: How to find out what type of error it is: Failure sending mail.

oMailMessage.IsBodyHtml = False
oMailMessage.Body = cEmailBody
Dim oSMTP As New SmtpClient

Try
oSMTP.Send(oMailMessage) (in this line I am getting the above err)
Catch ex as Exception
System.Diagnostics.Debug.WriteLine(ex.ToString() )
End Try

Re: How to find out what type of error it is: Failure sending mail.

This is a multi-part message in MIME format.

------=_NextPart_000_001C_01C84668.90290690
Content-Type: text/plain;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable

Well I had actuallt the code like the below: The debugger poped up and =
just said that the Failure sending mail.=20
and did not provide the reason. But from some reason in my computer =
under Visual Studio 2005, the Alert message did not pop up.=20
Just wondering why? (The debugger did).=20

Thanks,

Joe

Try
some code.....
oMailMessage.IsBodyHtml =3D False
oMailMessage.Body =3D cEmailBody

Dim oSMTP As New SmtpClient
oSMTP.Send(oMailMessage) (in this line I am getting the above err)

Catch smtpEx As SmtpException
ClientScript.RegisterStartupScript(Me.GetType(), "E-Mail Problem", =
String.Format("Alert('There was a problem in sending the email: {0}');", =
smtpEx.Message.Replace("'", "\'")), True)

Catch generalEx As Exception

ClientScript.RegisterStartupScript(Me.GetType(), "General Problem", =
String.Format("alert('There was a general problem: {0}');", =
generalEx.Message.Replace("'", "\'")), True)

End Try




"Scott M." wrote in message =
news:%23lIk0%23cRIHA.4444@TK2MSFTNGP02.phx.gbl...
Wrap the code in a try...catch block?


"JoeP" wrote in message =
news:%23i4RTOcRIHA.3516@TK2MSFTNGP02.phx.gbl...
Hi All,

How can I find the reason for such an error: Failure sending mail.

Some Code...

oMailMessage.IsBodyHtml =3D False
oMailMessage.Body =3D cEmailBody
Dim oSMTP As New SmtpClient
oSMTP.Send(oMailMessage) (in this line I am getting the above err)

Appreciate any feedback

Thanks,

Joe


------=_NextPart_000_001C_01C84668.90290690
Content-Type: text/html;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable



charset=3Diso-8859-1">

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

Wrap the code in a try...catch=20
block?

 

 

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com> wrote =
in message=20
=
href=3D"news:%23i4RTOcRIHA.3516@TK2MSFTNGP02.phx.gbl">news:% 23i4RTOcRIHA.=
3516@TK2MSFTNGP02.phx.gbl...

Hi All,

 

How can I find the reason for such =
an error:=20
Failure sending mail.

Some Code...

oMailMessage.IsBodyHtml =3D size=3D2>False
oMailMessage.Body =
cEmailBody

Dim oSMTP As New =
SmtpClient
color=3D#ff0000>oSMTP.Send(oMailMessage)   (in this line I =
am=20
getting the above err)

 

Appreciate any =
feedback

 

Thanks,

 

Joe

size=3D2> 

Re: How to find out what type of error it is: Failure sending mail.

Thanks,

Re: How to find out what type of error it is: Failure sending mail.

This is a multi-part message in MIME format.

------=_NextPart_000_0022_01C8466E.43F3D7E0
Content-Type: text/plain;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable

Hi All,

Ok, after checking into it I had some code after the End Try and that =
was the reason Alert() did not pop up.=20
Moving that code under the Try fixed the problem.

But I am trying to break the message into 2 lines:

ClientScript.RegisterStartupScript(Me.GetType(), "E-Mail Problem", =
String.Format("Alert('There was a problem in sending the email! Please =
call us by phone {0}');", smtpEx.Message.Replace("'", "\'")), True)

Now how do I bring the actual err line into the second line of the =
Alert()

There was a problem in sending the email! Please call us by phone.=20
Unable to cast object of type 'System.Int32' to type =
'System.Net.Mail.MailMessage'

Thanks,

Joe


"JoeP" wrote in message =
news:eGeSbJpRIHA.5988@TK2MSFTNGP02.phx.gbl...
Well I had actuallt the code like the below: The debugger poped up and =
just said that the Failure sending mail.=20
and did not provide the reason. But from some reason in my computer =
under Visual Studio 2005, the Alert message did not pop up.=20
Just wondering why? (The debugger did).=20

Thanks,

Joe

Try
some code.....
oMailMessage.IsBodyHtml =3D False
oMailMessage.Body =3D cEmailBody

Dim oSMTP As New SmtpClient
oSMTP.Send(oMailMessage) (in this line I am getting the above =
err)

Catch smtpEx As SmtpException
ClientScript.RegisterStartupScript(Me.GetType(), "E-Mail Problem", =
String.Format("Alert('There was a problem in sending the email: {0}');", =
smtpEx.Message.Replace("'", "\'")), True)

Catch generalEx As Exception

ClientScript.RegisterStartupScript(Me.GetType(), "General =
Problem", String.Format("alert('There was a general problem: {0}');", =
generalEx.Message.Replace("'", "\'")), True)

End Try




"Scott M." wrote in message =
news:%23lIk0%23cRIHA.4444@TK2MSFTNGP02.phx.gbl...
Wrap the code in a try...catch block?


"JoeP" wrote in message =
news:%23i4RTOcRIHA.3516@TK2MSFTNGP02.phx.gbl...
Hi All,

How can I find the reason for such an error: Failure sending mail.

Some Code...

oMailMessage.IsBodyHtml =3D False
oMailMessage.Body =3D cEmailBody
Dim oSMTP As New SmtpClient
oSMTP.Send(oMailMessage) (in this line I am getting the above =
err)

Appreciate any feedback

Thanks,

Joe


------=_NextPart_000_0022_01C8466E.43F3D7E0
Content-Type: text/html;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable



charset=3Diso-8859-1">

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com>=20
wrote in message =
href=3D"news:eGeSbJpRIHA.5988@TK2MSFTNGP02.phx.gbl">news:eGe SbJpRIHA.5988=
@TK2MSFTNGP02.phx.gbl...

Well I had actuallt =
the code=20
like the below: The debugger poped up and just said that the =
Failure=20
sending mail. 

and did not provide the reason. But =
from some=20
reason in my computer under Visual Studio 2005, the Alert =
message=20
did not pop up.

Just wondering why? (The debugger =
did).=20

 

Thanks,

 

color=3D#000000>Joe

Try

color=3D#000000>    some =
code.....
   =20
oMailMessage.IsBodyHtml =3D size=3D2>False
size=3D2>    oMailMessage.Body =3D =
cEmailBody

    Dim oSMTP As New=20
SmtpClient
   =20
oSMTP.Send(oMailMessage)   (in this line I am getting the =
above=20
err)

size=3D2>
Catch size=3D2> smtpEx As size=3D2>=20
SmtpException

   =20
ClientScript.RegisterStartupScript( size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"E-Mail Problem", color=3D#0000ff=20
size=3D2>String.Format( color=3D#800000=20
size=3D2>"Alert('There was a problem in sending the email: =
{0}');" size=3D2>, smtpEx.Message.Replace( size=3D2>"'", size=3D2>"\'")), size=3D2>True)

Catch =
generalEx=20
As =
Exception

   =20
ClientScript.RegisterStartupScript( size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"General Problem", color=3D#0000ff=20
size=3D2>String.Format( color=3D#800000=20
size=3D2>"alert('There was a general problem: {0}');" size=3D2>, generalEx.Message.Replace(
size=3D2>"'", size=3D2>"\'")), size=3D2>True)

End =
color=3D#0000ff size=3D2>Try

 

 

 

"Scott M." < href=3D"mailto:smar@nospam.nospam">smar@nospam.nospam> wrote in =
message=20
=
href=3D"news:%23lIk0%23cRIHA.4444@TK2MSFTNGP02.phx.gbl">news :%23lIk0%23cR=
IHA.4444@TK2MSFTNGP02.phx.gbl...

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

Wrap the code in a try...catch=20
block?

 

 

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com> =
wrote in=20
message =
href=3D"news:%23i4RTOcRIHA.3516@TK2MSFTNGP02.phx.gbl">news:% 23i4RTOcRIHA.=
3516@TK2MSFTNGP02.phx.gbl...

Hi All,

 

How can I find the reason for =
such an error:=20
Failure sending mail.

Some Code...

oMailMessage.IsBodyHtml =3D size=3D2>False
oMailMessage.Body =
cEmailBody

Dim oSMTP As New =
SmtpClient
color=3D#ff0000>oSMTP.Send(oMailMessage)   (in this line =
I am=20
getting the above err)

 

Appreciate any =
feedback

 

Thanks,

 

Joe

size=3D2> 

Re: How to find out what type of error it is: Failure sending mail.

This is a multi-part message in MIME format.

------=_NextPart_000_0028_01C84676.375E20A0
Content-Type: text/plain;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable

When you are in a Catch section, notice that the exception is passed to =
the catch as "ex". If you check out the properties of "ex", you can =
find out about the exception. Start with this:

Catch ex As Exception
console.writeline("Exception type is: " & ex.getType.toString)
console.writeline("Exception message is: " & ex.Message)


"JoeP" wrote in message =
news:%23XxCPgpRIHA.4476@TK2MSFTNGP06.phx.gbl...
Hi All,

Ok, after checking into it I had some code after the End Try and that =
was the reason Alert() did not pop up.=20
Moving that code under the Try fixed the problem.

But I am trying to break the message into 2 lines:

ClientScript.RegisterStartupScript(Me.GetType(), "E-Mail Problem", =
String.Format("Alert('There was a problem in sending the email! Please =
call us by phone {0}');", smtpEx.Message.Replace("'", "\'")), True)

Now how do I bring the actual err line into the second line of the =
Alert()

There was a problem in sending the email! Please call us by phone.=20
Unable to cast object of type 'System.Int32' to type =
'System.Net.Mail.MailMessage'

Thanks,

Joe


"JoeP" wrote in message =
news:eGeSbJpRIHA.5988@TK2MSFTNGP02.phx.gbl...
Well I had actuallt the code like the below: The debugger poped up =
and just said that the Failure sending mail.=20
and did not provide the reason. But from some reason in my computer =
under Visual Studio 2005, the Alert message did not pop up.=20
Just wondering why? (The debugger did).=20

Thanks,

Joe

Try
some code.....
oMailMessage.IsBodyHtml =3D False
oMailMessage.Body =3D cEmailBody

Dim oSMTP As New SmtpClient
oSMTP.Send(oMailMessage) (in this line I am getting the above =
err)

Catch smtpEx As SmtpException
ClientScript.RegisterStartupScript(Me.GetType(), "E-Mail =
Problem", String.Format("Alert('There was a problem in sending the =
email: {0}');", smtpEx.Message.Replace("'", "\'")), True)

Catch generalEx As Exception

ClientScript.RegisterStartupScript(Me.GetType(), "General =
Problem", String.Format("alert('There was a general problem: {0}');", =
generalEx.Message.Replace("'", "\'")), True)

End Try




"Scott M." wrote in message =
news:%23lIk0%23cRIHA.4444@TK2MSFTNGP02.phx.gbl...
Wrap the code in a try...catch block?


"JoeP" wrote in message =
news:%23i4RTOcRIHA.3516@TK2MSFTNGP02.phx.gbl...
Hi All,

How can I find the reason for such an error: Failure sending =
mail.

Some Code...

oMailMessage.IsBodyHtml =3D False
oMailMessage.Body =3D cEmailBody
Dim oSMTP As New SmtpClient
oSMTP.Send(oMailMessage) (in this line I am getting the above =
err)

Appreciate any feedback

Thanks,

Joe


------=_NextPart_000_0028_01C84676.375E20A0
Content-Type: text/html;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable



charset=3Diso-8859-1">

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com>=20
wrote in message =
href=3D"news:%23XxCPgpRIHA.4476@TK2MSFTNGP06.phx.gbl">news:% 23XxCPgpRIHA.=
4476@TK2MSFTNGP06.phx.gbl...

Hi All,

 

Ok, after checking into it I had some =
code after=20
the End Try color=3D#000000>and that was=20
the reason Alert() did not pop up.

Moving that code under the Try fixed =
the=20
problem.

 

But I am trying to break the message =
into 2=20
lines:

 

ClientScript.RegisterStartupScript( size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"E-Mail Problem", color=3D#0000ff=20
size=3D2>String.Format( color=3D#800000=20
size=3D2>"Alert('There was a problem in sending the email! Please call =
us by=20
phone {0}');", =
smtpEx.Message.Replace( color=3D#800000 size=3D2>"'", color=3D#800000=20
size=3D2>"\'")), size=3D2>True)

 

Now how do I bring the actual err =
line into=20
the second line of the Alert()

There was a =
problem in=20
sending the email! Please call us by phone. 
Unable to cast =
object of=20
type 'System.Int32' to type =
'System.Net.Mail.MailMessage'

 

Thanks,

 

Joe

 

 

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com> wrote =
in message=20
=
href=3D"news:eGeSbJpRIHA.5988@TK2MSFTNGP02.phx.gbl">news:eGe SbJpRIHA.5988=
@TK2MSFTNGP02.phx.gbl...

Well I had actuallt =
the code=20
like the below: The debugger poped up and just said that the=20
Failure sending mail. 

and did not provide the reason. =
But from some=20
reason in my computer under Visual Studio 2005, the Alert =
message=20
did not pop up.

Just wondering why? (The debugger =
did).=20

 

Thanks,

size=3D2> 

color=3D#000000>Joe

Try

color=3D#000000>    some =
code.....
   =20
oMailMessage.IsBodyHtml =3D size=3D2>False
size=3D2>    oMailMessage.Body =3D =
cEmailBody

    Dim oSMTP As New =

SmtpClient
   =20
oSMTP.Send(oMailMessage)   (in this line I am getting the =
above=20
err)

size=3D2>
Catch smtpEx color=3D#0000ff=20
size=3D2>As SmtpException

   =20
ClientScript.RegisterStartupScript( size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"E-Mail Problem", color=3D#0000ff=20
size=3D2>String.Format( color=3D#800000=20
size=3D2>"Alert('There was a problem in sending the email: =
{0}');" size=3D2>, smtpEx.Message.Replace( size=3D2>"'", size=3D2>"\'")), size=3D2>True)

Catch =
generalEx=20
As =
Exception

   =20
ClientScript.RegisterStartupScript( size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"General Problem", color=3D#0000ff=20
size=3D2>String.Format( color=3D#800000=20
size=3D2>"alert('There was a general problem: {0}');" size=3D2>, generalEx.Message.Replace( color=3D#800000=20
size=3D2>"'", size=3D2>"\'")), size=3D2>True)

End =
color=3D#0000ff size=3D2>Try

 

 

 

"Scott M." < href=3D"mailto:smar@nospam.nospam">smar@nospam.nospam> wrote =
in message=20
=
href=3D"news:%23lIk0%23cRIHA.4444@TK2MSFTNGP02.phx.gbl">news :%23lIk0%23cR=
IHA.4444@TK2MSFTNGP02.phx.gbl...

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

Wrap the code in a try...catch=20
block?

 

 

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com> =
wrote in=20
message =
href=3D"news:%23i4RTOcRIHA.3516@TK2MSFTNGP02.phx.gbl">news:% 23i4RTOcRIHA.=
3516@TK2MSFTNGP02.phx.gbl...

Hi All,

 

How can I find the reason for =
such an=20
error: Failure sending mail.

size=3D2>

Some Code...

oMailMessage.IsBodyHtml =3D size=3D2>False
oMailMessage.Body =
cEmailBody

Dim oSMTP As New =
SmtpClient
color=3D#ff0000>oSMTP.Send(oMailMessage)   (in this =
line I am=20
getting the above err)

 

Appreciate any =
feedback

 

Thanks,

 

Joe

=
size=3D2> 

UOTE>

------=_NextPart_000_0028_01C84676.375E20A0--

Re: How to find out what type of error it is: Failure sending mail.

This is a multi-part message in MIME format.

------=_NextPart_000_0014_01C846F3.A3B0F660
Content-Type: text/plain;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable

My question is now how can I concatenate the 2 strings together into the =
message box for the Alert()?

ClientScript.RegisterStartupScript(Me.GetType(), "E-Mail Problem", =
String.Format("Alert('There was a problem in sending the email! Please =
call us by phone {0}');", smtpEx.Message.Replace("'", "\'")), True)

String 1 is: 'There was a problem in sending the email! Please call us =
by phone!=20
String 2 is:smtpEx.Message

Thanks.


"Scott M." wrote in message =
news:OAtGO$pRIHA.4180@TK2MSFTNGP06.phx.gbl...
When you are in a Catch section, notice that the exception is passed =
to the catch as "ex". If you check out the properties of "ex", you can =
find out about the exception. Start with this:

Catch ex As Exception
console.writeline("Exception type is: " & ex.getType.toString)
console.writeline("Exception message is: " & ex.Message)


"JoeP" wrote in message =
news:%23XxCPgpRIHA.4476@TK2MSFTNGP06.phx.gbl...
Hi All,

Ok, after checking into it I had some code after the End Try and =
that was the reason Alert() did not pop up.=20
Moving that code under the Try fixed the problem.

But I am trying to break the message into 2 lines:

ClientScript.RegisterStartupScript(Me.GetType(), "E-Mail Problem", =
String.Format("Alert('There was a problem in sending the email! Please =
call us by phone {0}');", smtpEx.Message.Replace("'", "\'")), True)

Now how do I bring the actual err line into the second line of the =
Alert()

There was a problem in sending the email! Please call us by phone.=20
Unable to cast object of type 'System.Int32' to type =
'System.Net.Mail.MailMessage'

Thanks,

Joe


"JoeP" wrote in message =
news:eGeSbJpRIHA.5988@TK2MSFTNGP02.phx.gbl...
Well I had actuallt the code like the below: The debugger poped up =
and just said that the Failure sending mail.=20
and did not provide the reason. But from some reason in my =
computer under Visual Studio 2005, the Alert message did not pop up.=20
Just wondering why? (The debugger did).=20

Thanks,

Joe

Try
some code.....
oMailMessage.IsBodyHtml =3D False
oMailMessage.Body =3D cEmailBody

Dim oSMTP As New SmtpClient
oSMTP.Send(oMailMessage) (in this line I am getting the =
above err)

Catch smtpEx As SmtpException
ClientScript.RegisterStartupScript(Me.GetType(), "E-Mail =
Problem", String.Format("Alert('There was a problem in sending the =
email: {0}');", smtpEx.Message.Replace("'", "\'")), True)

Catch generalEx As Exception

ClientScript.RegisterStartupScript(Me.GetType(), "General =
Problem", String.Format("alert('There was a general problem: {0}');", =
generalEx.Message.Replace("'", "\'")), True)

End Try




"Scott M." wrote in message =
news:%23lIk0%23cRIHA.4444@TK2MSFTNGP02.phx.gbl...
Wrap the code in a try...catch block?


"JoeP" wrote in message =
news:%23i4RTOcRIHA.3516@TK2MSFTNGP02.phx.gbl...
Hi All,

How can I find the reason for such an error: Failure sending =
mail.

Some Code...

oMailMessage.IsBodyHtml =3D False
oMailMessage.Body =3D cEmailBody
Dim oSMTP As New SmtpClient
oSMTP.Send(oMailMessage) (in this line I am getting the =
above err)

Appreciate any feedback

Thanks,

Joe


------=_NextPart_000_0014_01C846F3.A3B0F660
Content-Type: text/html;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable



charset=3Diso-8859-1">

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

When you are in a Catch section, =
notice that the=20
exception is passed to the catch as "ex".  If you check out the=20
properties of "ex", you can find out about the exception.  Start =
with=20
this:

 

Catch ex As Exception

    =
console.writeline("Exception=20
type is: " & ex.getType.toString)

   =20
console.writeline("Exception message is: " & =
ex.Message)

 

 

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com> wrote =
in message=20
=
href=3D"news:%23XxCPgpRIHA.4476@TK2MSFTNGP06.phx.gbl">news:% 23XxCPgpRIHA.=
4476@TK2MSFTNGP06.phx.gbl...

Hi All,

 

Ok, after checking into it I had =
some code=20
after the End Try color=3D#000000>and that was the reason Alert() did not pop up. =

Moving that code under the Try =
fixed the=20
problem.

 

But I am trying to break the =
message into 2=20
lines:

 

ClientScript.RegisterStartupScript( size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"E-Mail Problem", color=3D#0000ff=20
size=3D2>String.Format( color=3D#800000=20
size=3D2>"Alert('There was a problem in sending the email! Please =
call us by=20
phone {0}');", =
smtpEx.Message.Replace( color=3D#800000 size=3D2>"'", color=3D#800000=20
size=3D2>"\'")), size=3D2>True)

 

Now how do I bring the actual err=20
line into the second line of the Alert()

There was a =
problem in=20
sending the email! Please call us by phone. 
Unable to cast =
object=20
of type 'System.Int32' to type=20
'System.Net.Mail.MailMessage'

 

Thanks,

 

Joe

 

 

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com> =
wrote in=20
message =
href=3D"news:eGeSbJpRIHA.5988@TK2MSFTNGP02.phx.gbl">news:eGe SbJpRIHA.5988=
@TK2MSFTNGP02.phx.gbl...

Well I had actuallt =
the code=20
like the below: The debugger poped up and just said that the=20
Failure sending mail. 

and did not provide the reason. =
But from=20
some reason in my computer under Visual Studio 2005, the =
Alert=20
message did not pop up.

Just wondering why? (The =
debugger did).=20

 

Thanks,

size=3D2> 

color=3D#000000>Joe

Try

color=3D#000000>    some =
code.....
   =20
oMailMessage.IsBodyHtml =3D size=3D2>False
size=3D2>    oMailMessage.Body =3D =
cEmailBody

    Dim oSMTP As =
New=20
SmtpClient
   =20
oSMTP.Send(oMailMessage)   (in this line I am getting =
the above=20
err)

size=3D2>
Catch smtpEx color=3D#0000ff=20
size=3D2>As SmtpException

   =20
ClientScript.RegisterStartupScript( size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"E-Mail Problem", color=3D#0000ff=20
size=3D2>String.Format( color=3D#800000=20
size=3D2>"Alert('There was a problem in sending the email:=20
{0}');", smtpEx.Message.Replace(
color=3D#800000 size=3D2>"'", color=3D#800000=20
size=3D2>"\'")), color=3D#0000ff=20
size=3D2>True)

Catch size=3D2> generalEx=20
As =
Exception

   =20
ClientScript.RegisterStartupScript( size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"General Problem", color=3D#0000ff=20
size=3D2>String.Format( color=3D#800000=20
size=3D2>"alert('There was a general problem: {0}');" size=3D2>, generalEx.Message.Replace( color=3D#800000=20
size=3D2>"'", size=3D2>"\'")), color=3D#0000ff=20
size=3D2>True)

End =
color=3D#0000ff size=3D2>Try

 

 

 

"Scott M." < href=3D"mailto:smar@nospam.nospam">smar@nospam.nospam> =
wrote in=20
message =
href=3D"news:%23lIk0%23cRIHA.4444@TK2MSFTNGP02.phx.gbl">news :%23lIk0%23cR=
IHA.4444@TK2MSFTNGP02.phx.gbl...

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

Wrap the code in a try...catch=20
block?

 

 

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: =
5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com> =
wrote in=20
message =
href=3D"news:%23i4RTOcRIHA.3516@TK2MSFTNGP02.phx.gbl">news:% 23i4RTOcRIHA.=
3516@TK2MSFTNGP02.phx.gbl...

Hi All,

 

How can I find the reason for =
such an=20
error: Failure sending mail.

size=3D2>

Some Code...

oMailMessage.IsBodyHtml =3D size=3D2>False
oMailMessage.Body =
cEmailBody

Dim oSMTP As New =
SmtpClient
color=3D#ff0000>oSMTP.Send(oMailMessage)   (in this =
line I am=20
getting the above err)

 

Appreciate any =
feedback

 

Thanks,

 

Joe

=
size=3D2> 

UOTE>

------=_NextPart_000_0014_01C846F3.A3B0F660--

Re: How to find out what type of error it is: Failure sending mail.

This is a multi-part message in MIME format.

------=_NextPart_000_000C_01C84741.A46E0860
Content-Type: text/plain;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable

Generally, you don't want to take information from the exception and =
send it directly to the client as this can expose security holes & =
proprietary code. Instead you find out what exception you have =
encountered in the Try...Catch and then you write whatever you find to =
be appropriate to the client based on that information. If you really =
want to include exception information directly in your output, it is a =
simple matter of concatenation:

ClientScript.RegisterStartupScript(Me.GetType(), "E-Mail Problem", =
String.Format("Alert('There was a {0} problem in sending the email! =
Please call us by phone {1}');", ex.GetType.ToString(), =
smtpEx.Message.Replace("'", "\'")), True)


"JoeP" wrote in message =
news:eLETt1xRIHA.4180@TK2MSFTNGP06.phx.gbl...
My question is now how can I concatenate the 2 strings together into =
the message box for the Alert()?

ClientScript.RegisterStartupScript(Me.GetType(), "E-Mail Problem", =
String.Format("Alert('There was a problem in sending the email! Please =
call us by phone {0}');", smtpEx.Message.Replace("'", "\'")), True)

String 1 is: 'There was a problem in sending the email! Please call us =
by phone!=20
String 2 is:smtpEx.Message

Thanks.


"Scott M." wrote in message =
news:OAtGO$pRIHA.4180@TK2MSFTNGP06.phx.gbl...
When you are in a Catch section, notice that the exception is passed =
to the catch as "ex". If you check out the properties of "ex", you can =
find out about the exception. Start with this:

Catch ex As Exception
console.writeline("Exception type is: " & ex.getType.toString)
console.writeline("Exception message is: " & ex.Message)


"JoeP" wrote in message =
news:%23XxCPgpRIHA.4476@TK2MSFTNGP06.phx.gbl...
Hi All,

Ok, after checking into it I had some code after the End Try and =
that was the reason Alert() did not pop up.=20
Moving that code under the Try fixed the problem.

But I am trying to break the message into 2 lines:

ClientScript.RegisterStartupScript(Me.GetType(), "E-Mail Problem", =
String.Format("Alert('There was a problem in sending the email! Please =
call us by phone {0}');", smtpEx.Message.Replace("'", "\'")), True)

Now how do I bring the actual err line into the second line of the =
Alert()

There was a problem in sending the email! Please call us by phone. =

Unable to cast object of type 'System.Int32' to type =
'System.Net.Mail.MailMessage'

Thanks,

Joe


"JoeP" wrote in message =
news:eGeSbJpRIHA.5988@TK2MSFTNGP02.phx.gbl...
Well I had actuallt the code like the below: The debugger poped =
up and just said that the Failure sending mail.=20
and did not provide the reason. But from some reason in my =
computer under Visual Studio 2005, the Alert message did not pop up.=20
Just wondering why? (The debugger did).=20

Thanks,

Joe

Try
some code.....
oMailMessage.IsBodyHtml =3D False
oMailMessage.Body =3D cEmailBody

Dim oSMTP As New SmtpClient
oSMTP.Send(oMailMessage) (in this line I am getting the =
above err)

Catch smtpEx As SmtpException
ClientScript.RegisterStartupScript(Me.GetType(), "E-Mail =
Problem", String.Format("Alert('There was a problem in sending the =
email: {0}');", smtpEx.Message.Replace("'", "\'")), True)

Catch generalEx As Exception

ClientScript.RegisterStartupScript(Me.GetType(), "General =
Problem", String.Format("alert('There was a general problem: {0}');", =
generalEx.Message.Replace("'", "\'")), True)

End Try




"Scott M." wrote in message =
news:%23lIk0%23cRIHA.4444@TK2MSFTNGP02.phx.gbl...
Wrap the code in a try...catch block?


"JoeP" wrote in message =
news:%23i4RTOcRIHA.3516@TK2MSFTNGP02.phx.gbl...
Hi All,

How can I find the reason for such an error: Failure sending =
mail.

Some Code...

oMailMessage.IsBodyHtml =3D False
oMailMessage.Body =3D cEmailBody
Dim oSMTP As New SmtpClient
oSMTP.Send(oMailMessage) (in this line I am getting the =
above err)

Appreciate any feedback

Thanks,

Joe


------=_NextPart_000_000C_01C84741.A46E0860
Content-Type: text/html;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable



charset=3Diso-8859-1">

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com>=20
wrote in message =
href=3D"news:eLETt1xRIHA.4180@TK2MSFTNGP06.phx.gbl">news:eLE Tt1xRIHA.4180=
@TK2MSFTNGP06.phx.gbl...

My question is now how can I =
concatenate the=20
2 strings together into the message box for the Alert()?

 

ClientScript.RegisterStartupScript( color=3D#0000ff=20
size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"E-Mail Problem", color=3D#0000ff=20
size=3D2>String.Format( color=3D#800000=20
size=3D2>"Alert('There was a problem in sending the email! Please call =
us by=20
phone {0}');", =
smtpEx.Message.Replace( color=3D#800000 size=3D2>"'", color=3D#800000=20
size=3D2>"\'")), size=3D2>True)

 

String 1 is: color=3D#800000>'There was a problem in sending the email! Please call =
us by=20
phone! 

String 2 =
is: color=3D#000000>smtpEx.Message

 

Thanks.

 

 

"Scott M." < href=3D"mailto:smar@nospam.nospam">smar@nospam.nospam> wrote in =
message=20
=
href=3D"news:OAtGO$pRIHA.4180@TK2MSFTNGP06.phx.gbl">news:OAt GO$pRIHA.4180=
@TK2MSFTNGP06.phx.gbl...

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

When you are in a Catch section, =
notice that=20
the exception is passed to the catch as "ex".  If you check out =
the=20
properties of "ex", you can find out about the exception.  =
Start with=20
this:

 

Catch ex As Exception

    =
console.writeline("Exception=20
type is: " & ex.getType.toString)

   =20
console.writeline("Exception message is: " &=20
ex.Message)

 

 

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com> =
wrote in=20
message =
href=3D"news:%23XxCPgpRIHA.4476@TK2MSFTNGP06.phx.gbl">news:% 23XxCPgpRIHA.=
4476@TK2MSFTNGP06.phx.gbl...

Hi All,

 

Ok, after checking into it I had =
some code=20
after the End Try color=3D#000000>and that was the reason Alert() did not pop =
up.=20

Moving that code under the Try =
fixed the=20
problem.

 

But I am trying to break the =
message into 2=20
lines:

 

ClientScript.RegisterStartupScript( size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"E-Mail Problem", color=3D#0000ff=20
size=3D2>String.Format( color=3D#800000=20
size=3D2>"Alert('There was a problem in sending the email! Please =
call us by=20
phone {0}');",=20
smtpEx.Message.Replace( size=3D2>"'" size=3D2>, "\'" size=3D2>)),=20
True size=3D2>)

 

Now how do I bring the actual err =

line into the second line of the Alert()

There was a =
problem in=20
sending the email! Please call us by phone. 
Unable to =
cast object=20
of type 'System.Int32' to type=20
'System.Net.Mail.MailMessage'

 

Thanks,

 

Joe

 

 

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com> =
wrote in=20
message =
href=3D"news:eGeSbJpRIHA.5988@TK2MSFTNGP02.phx.gbl">news:eGe SbJpRIHA.5988=
@TK2MSFTNGP02.phx.gbl...

Well I had actuallt =
the code=20
like the below: The debugger poped up and just said that =
the=20
Failure sending mail. 

and did not provide the =
reason. But from=20
some reason in my computer under Visual Studio =
2005, the Alert=20
message did not pop up.

Just wondering why? (The =
debugger did).=20

 

Thanks,

size=3D2> 

color=3D#000000>Joe

Try

color=3D#000000>    some =
code.....
   =20
oMailMessage.IsBodyHtml =3D size=3D2>False
    =
oMailMessage.Body=20
=3D cEmailBody

    Dim oSMTP As =
New=20
SmtpClient
   =20
oSMTP.Send(oMailMessage)   (in this line I am getting =
the=20
above err)

size=3D2>
Catch smtpEx color=3D#0000ff=20
size=3D2>As SmtpException

   =20
ClientScript.RegisterStartupScript( size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"E-Mail Problem", color=3D#0000ff=20
size=3D2>String.Format( color=3D#800000=20
size=3D2>"Alert('There was a problem in sending the email:=20
{0}');", =
smtpEx.Message.Replace( color=3D#800000 size=3D2>"'", color=3D#800000=20
size=3D2>"\'")), color=3D#0000ff=20
size=3D2>True)

Catch size=3D2> generalEx=20
As =
Exception

   =20
ClientScript.RegisterStartupScript( size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"General Problem", color=3D#0000ff=20
size=3D2>String.Format( color=3D#800000=20
size=3D2>"alert('There was a general problem: =
{0}');" size=3D2>, generalEx.Message.Replace( color=3D#800000=20
size=3D2>"'",
size=3D2>"\'")), color=3D#0000ff=20
size=3D2>True)

End size=3D2>=20
size=3D2>Try

 

 

 

"Scott M." < href=3D"mailto:smar@nospam.nospam">smar@nospam.nospam> =
wrote in=20
message =
href=3D"news:%23lIk0%23cRIHA.4444@TK2MSFTNGP02.phx.gbl">news :%23lIk0%23cR=
IHA.4444@TK2MSFTNGP02.phx.gbl...

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: =
5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

Wrap the code in a =
try...catch=20
block?

 

 

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: =
5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < =
href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com> wrote in=20
message =
href=3D"news:%23i4RTOcRIHA.3516@TK2MSFTNGP02.phx.gbl">news:% 23i4RTOcRIHA.=
3516@TK2MSFTNGP02.phx.gbl...

Hi All,

 

How can I find the reason =
for such an=20
error: Failure sending mail.

size=3D2>

Some Code...

oMailMessage.IsBodyHtml =3D color=3D#0000ff=20
size=3D2>False
oMailMessage.Body =
=
cEmailBody

Dim oSMTP As New =
SmtpClient
color=3D#ff0000>oSMTP.Send(oMailMessage)   (in =
this line I=20
am getting the above err)

 

Appreciate any =
feedback

 

Thanks,

 

Joe

=
size=3D2> 

UOTE>

------=_NextPart_000_000C_01C84741.A46E0860--

Re: How to find out what type of error it is: Failure sending mail.

This is a multi-part message in MIME format.

------=_NextPart_000_000A_01C847A4.A104BCB0
Content-Type: text/plain;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable

Ok Thanks
"Scott M." wrote in message =
news:uk0K6s2RIHA.4400@TK2MSFTNGP06.phx.gbl...
Generally, you don't want to take information from the exception and =
send it directly to the client as this can expose security holes & =
proprietary code. Instead you find out what exception you have =
encountered in the Try...Catch and then you write whatever you find to =
be appropriate to the client based on that information. If you really =
want to include exception information directly in your output, it is a =
simple matter of concatenation:

ClientScript.RegisterStartupScript(Me.GetType(), "E-Mail Problem", =
String.Format("Alert('There was a {0} problem in sending the email! =
Please call us by phone {1}');", ex.GetType.ToString(), =
smtpEx.Message.Replace("'", "\'")), True)


"JoeP" wrote in message =
news:eLETt1xRIHA.4180@TK2MSFTNGP06.phx.gbl...
My question is now how can I concatenate the 2 strings together into =
the message box for the Alert()?

ClientScript.RegisterStartupScript(Me.GetType(), "E-Mail Problem", =
String.Format("Alert('There was a problem in sending the email! Please =
call us by phone {0}');", smtpEx.Message.Replace("'", "\'")), True)

String 1 is: 'There was a problem in sending the email! Please call =
us by phone!=20
String 2 is:smtpEx.Message

Thanks.


"Scott M." wrote in message =
news:OAtGO$pRIHA.4180@TK2MSFTNGP06.phx.gbl...
When you are in a Catch section, notice that the exception is =
passed to the catch as "ex". If you check out the properties of "ex", =
you can find out about the exception. Start with this:

Catch ex As Exception
console.writeline("Exception type is: " & ex.getType.toString)
console.writeline("Exception message is: " & ex.Message)


"JoeP" wrote in message =
news:%23XxCPgpRIHA.4476@TK2MSFTNGP06.phx.gbl...
Hi All,

Ok, after checking into it I had some code after the End Try and =
that was the reason Alert() did not pop up.=20
Moving that code under the Try fixed the problem.

But I am trying to break the message into 2 lines:

ClientScript.RegisterStartupScript(Me.GetType(), "E-Mail =
Problem", String.Format("Alert('There was a problem in sending the =
email! Please call us by phone {0}');", smtpEx.Message.Replace("'", =
"\'")), True)

Now how do I bring the actual err line into the second line of =
the Alert()

There was a problem in sending the email! Please call us by =
phone.=20
Unable to cast object of type 'System.Int32' to type =
'System.Net.Mail.MailMessage'

Thanks,

Joe


"JoeP" wrote in message =
news:eGeSbJpRIHA.5988@TK2MSFTNGP02.phx.gbl...
Well I had actuallt the code like the below: The debugger =
poped up and just said that the Failure sending mail.=20
and did not provide the reason. But from some reason in my =
computer under Visual Studio 2005, the Alert message did not pop up.=20
Just wondering why? (The debugger did).=20

Thanks,

Joe

Try
some code.....
oMailMessage.IsBodyHtml =3D False
oMailMessage.Body =3D cEmailBody

Dim oSMTP As New SmtpClient
oSMTP.Send(oMailMessage) (in this line I am getting the =
above err)

Catch smtpEx As SmtpException
ClientScript.RegisterStartupScript(Me.GetType(), "E-Mail =
Problem", String.Format("Alert('There was a problem in sending the =
email: {0}');", smtpEx.Message.Replace("'", "\'")), True)

Catch generalEx As Exception

ClientScript.RegisterStartupScript(Me.GetType(), "General =
Problem", String.Format("alert('There was a general problem: {0}');", =
generalEx.Message.Replace("'", "\'")), True)

End Try




"Scott M." wrote in message =
news:%23lIk0%23cRIHA.4444@TK2MSFTNGP02.phx.gbl...
Wrap the code in a try...catch block?


"JoeP" wrote in message =
news:%23i4RTOcRIHA.3516@TK2MSFTNGP02.phx.gbl...
Hi All,

How can I find the reason for such an error: Failure =
sending mail.

Some Code...

oMailMessage.IsBodyHtml =3D False
oMailMessage.Body =3D cEmailBody
Dim oSMTP As New SmtpClient
oSMTP.Send(oMailMessage) (in this line I am getting the =
above err)

Appreciate any feedback

Thanks,

Joe


------=_NextPart_000_000A_01C847A4.A104BCB0
Content-Type: text/html;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable



charset=3Diso-8859-1">

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"Scott M." < href=3D"mailto:smar@nospam.nospam">smar@nospam.nospam> wrote in =
message=20
=
href=3D"news:uk0K6s2RIHA.4400@TK2MSFTNGP06.phx.gbl">news:uk0 K6s2RIHA.4400=
@TK2MSFTNGP06.phx.gbl...

Generally, you don't want to take =
information=20
from the exception and send it directly to the client as this can =
expose=20
security holes & proprietary code.  Instead you find out what =

exception you have encountered in the Try...Catch and then you write =
whatever=20
you find to be appropriate to the client based on that =
information.  If=20
you really want to include exception information directly in your =
output, it=20
is a simple matter of concatenation:

 

ClientScript.RegisterStartupScript( color=3D#0000ff=20
size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"E-Mail Problem", color=3D#0000ff=20
size=3D2>String.Format( color=3D#800000=20
size=3D2>"Alert('There was a {0} problem in sending the email! =
Please call=20
us by phone {1}');",=20
ex.GetType.ToString(), smtpEx.Message.Replace( color=3D#800000=20
size=3D2>"'", size=3D2>"\'")), size=3D2>True)

 

 

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com> wrote =
in message=20
=
href=3D"news:eLETt1xRIHA.4180@TK2MSFTNGP06.phx.gbl">news:eLE Tt1xRIHA.4180=
@TK2MSFTNGP06.phx.gbl...

My question is now how can I =
concatenate=20
the 2 strings together into the message box for the =
Alert()?

 

ClientScript.RegisterStartupScript( color=3D#0000ff=20
size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"E-Mail Problem", color=3D#0000ff=20
size=3D2>String.Format( color=3D#800000=20
size=3D2>"Alert('There was a problem in sending the email! Please =
call us by=20
phone {0}');", =
smtpEx.Message.Replace( color=3D#800000 size=3D2>"'", color=3D#800000=20
size=3D2>"\'")), size=3D2>True size=3D2>)

 

String 1 is: color=3D#800000>'There was a problem in sending the email! Please =
call us by=20
phone! 

String 2 =
is: color=3D#000000>smtpEx.Message

 

Thanks.

 

 

"Scott M." < href=3D"mailto:smar@nospam.nospam">smar@nospam.nospam> wrote =
in message=20
=
href=3D"news:OAtGO$pRIHA.4180@TK2MSFTNGP06.phx.gbl">news:OAt GO$pRIHA.4180=
@TK2MSFTNGP06.phx.gbl...

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

When you are in a Catch section, =
notice that=20
the exception is passed to the catch as "ex".  If you check =
out the=20
properties of "ex", you can find out about the exception.  =
Start with=20
this:

 

Catch ex As =
Exception

   =20
console.writeline("Exception type is: " &=20
ex.getType.toString)

   =20
console.writeline("Exception message is: " &=20
ex.Message)

 

 

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com> =
wrote in=20
message =
href=3D"news:%23XxCPgpRIHA.4476@TK2MSFTNGP06.phx.gbl">news:% 23XxCPgpRIHA.=
4476@TK2MSFTNGP06.phx.gbl...

Hi All,

 

Ok, after checking into it I =
had some code=20
after the End Try color=3D#000000>and that was the reason Alert() did not pop =
up.=20

Moving that code under the Try =
fixed the=20
problem.

 

But I am trying to break the =
message into 2=20
lines:

 

ClientScript.RegisterStartupScript( size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"E-Mail Problem", color=3D#0000ff=20
size=3D2>String.Format( color=3D#800000=20
size=3D2>"Alert('There was a problem in sending the email! =
Please call us=20
by phone {0}');",=20
smtpEx.Message.Replace( size=3D2>"'" size=3D2>, size=3D2>"\'")),=20
True size=3D2>)

 

Now how do I bring the actual =
err=20
line into the second line of the Alert()

There was =
a problem in=20
sending the email! Please call us by phone. 
Unable to =
cast=20
object of type 'System.Int32' to type=20
'System.Net.Mail.MailMessage'

 

Thanks,

 

Joe

 

 

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: =
5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com> =
wrote in=20
message =
href=3D"news:eGeSbJpRIHA.5988@TK2MSFTNGP02.phx.gbl">news:eGe SbJpRIHA.5988=
@TK2MSFTNGP02.phx.gbl...

Well I had actuallt =
the code=20
like the below: The debugger poped up and just said that =
the=20
Failure sending mail. 

and did not provide the =
reason. But=20
from some reason in my computer under Visual Studio=20
2005, the Alert message did not pop up.

Just wondering why? (The =
debugger did).=20

 

Thanks,

size=3D2> 

color=3D#000000>Joe

Try

color=3D#000000>    some =
code.....
   =20
oMailMessage.IsBodyHtml =3D size=3D2>False
   =20
oMailMessage.Body =3D cEmailBody

    Dim oSMTP =
As New=20
SmtpClient
   =20
oSMTP.Send(oMailMessage)   (in this line I am =
getting the=20
above err)

size=3D2>
Catch smtpEx color=3D#0000ff=20
size=3D2>As SmtpException

   =20
ClientScript.RegisterStartupScript( color=3D#0000ff=20
size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"E-Mail Problem", color=3D#0000ff size=3D2>String size=3D2>.Format( color=3D#800000 size=3D2>"Alert('There was a problem in =
sending the email:=20
{0}');", =
smtpEx.Message.Replace( color=3D#800000 size=3D2>"'", =
color=3D#800000 size=3D2>"\'")), =
color=3D#0000ff size=3D2>True)

Catch size=3D2>=20
generalEx As size=3D2>=20
Exception

   =20
ClientScript.RegisterStartupScript( color=3D#0000ff=20
size=3D2>Me.GetType(), color=3D#800000=20
size=3D2>"General Problem",
color=3D#0000ff size=3D2>String size=3D2>.Format( color=3D#800000 size=3D2>"alert('There was a general problem:=20
{0}');" size=3D2>, generalEx.Message.Replace( color=3D#800000=20
size=3D2>"'", color=3D#800000=20
size=3D2>"\'")), color=3D#0000ff=20
size=3D2>True)

End size=3D2>=20
size=3D2>Try

 

 

 

"Scott M." < href=3D"mailto:smar@nospam.nospam">smar@nospam.nospam> =
wrote in=20
message =
href=3D"news:%23lIk0%23cRIHA.4444@TK2MSFTNGP02.phx.gbl">news :%23lIk0%23cR=
IHA.4444@TK2MSFTNGP02.phx.gbl...

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: =
5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

Wrap the code in a =
try...catch=20
block?

 

 

style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: =
5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">

"JoeP" < =
href=3D"mailto:NoSpam@Hotmail.com">NoSpam@Hotmail.com> wrote=20
in message =
href=3D"news:%23i4RTOcRIHA.3516@TK2MSFTNGP02.phx.gbl">news:% 23i4RTOcRIHA.=
3516@TK2MSFTNGP02.phx.gbl...

Hi All,

 

How can I find the reason =
for such an=20
error: Failure sending mail.

size=3D2>

Some Code...

oMailMessage.IsBodyHtml =3D color=3D#0000ff=20
size=3D2>False
oMailMessage.Body =
=
cEmailBody

Dim oSMTP As New =
SmtpClient
color=3D#ff0000>oSMTP.Send(oMailMessage)   (in =
this line I=20
am getting the above err)

 

Appreciate any =
feedback

 

Thanks,

 

Joe

=
size=3D2> 

UOTE>

------=_NextPart_000_000A_01C847A4.A104BCB0--