shell script - generate a report with dir and # files
am 11.01.2008 20:51:30 von bhaveshahGurus,
I've a command which generates output as below:
foo.com shahb 485 /ms4/3C/12/70674
foo.com shahb Aix /ms4/62/12/67626
foo.com shahb Data_Growth /ms4/7C/1E/35066
foo.com shahb "Deleted Messages" /ms4/21/08/30698
foo.com shahb Drafts /ms2/31/1F/13832
foo.com shahb DR /ms4/32/06/96855
col 1 - domain
col2 - user
col3 - dir name
col3 - physical dir path
I have to write a script which generates a report for 1000 such users
with the no of files in each such dir. The report output should be
similar to:
User DIR # files
shahb Aix 445
shahb DR 2000
I can get the #files in each dir with the for loop as below:
for DIR in `/opt/sbin/mbox_path foo.com shahb | awk -F"\t" '{print
$4}'`; do echo "$DIR"; ls $DIR | wc -l | tr -d " "; done
This will give me the #files in folder but don't know who to relate to
the folder name and generate a report.
Any Help is greately appreciated.
Thanks & Regards