how to remove blocks between nested brackets
am 31.01.2008 13:55:22 von si
Beeing new to perl and not wanting to learn using it like assembler, I
need to delete parts of a single line (possibly long) that are enclosed
between nested brackets:
abcd efgh [ij: 123-[456]-klm; nop-789]; qrst; uvw [xyz: 98-76-[ef]; gh;
ijkl] (mnop)
The comments between [] must be discarded to split with ';' delimiter.
The expected result is:
array[0] == "abcd efgh"
array[1] == "qrst"
array[2] == "uvw (mnop)"
Thanks for a magic formula.
Re: how to remove blocks between nested brackets
am 31.01.2008 14:08:46 von someone
Si wrote:
> Beeing new to perl and not wanting to learn using it like assembler, I
> need to delete parts of a single line (possibly long) that are enclosed
> between nested brackets:
>
> abcd efgh [ij: 123-[456]-klm; nop-789]; qrst; uvw [xyz: 98-76-[ef]; gh;
> ijkl] (mnop)
>
> The comments between [] must be discarded to split with ';' delimiter.
> The expected result is:
> array[0] == "abcd efgh"
> array[1] == "qrst"
> array[2] == "uvw (mnop)"
$ perl -le'
my $line = q{abcd efgh [ij: 123-[456]-klm; nop-789]; qrst; uvw [xyz:
98-76-[ef]; gh; ijkl] (mnop)};
1 while $line =~ s/\[[^][]*]//g;
my @array = split /\s*;\s*/, $line;
print qq["$_"] for @array;
'
"abcd efgh"
"qrst"
"uvw (mnop)"
John
--
Perl isn't a toolbox, but a small machine shop where you
can special-order certain sorts of tools at low cost and
in short order. -- Larry Wall
Re: how to remove blocks between nested brackets
am 31.01.2008 17:20:16 von Abigail
_
Si (silicium_at_h@rmony-p.ath.cx) wrote on VCCLXVI September MCMXCIII in
:
:) Beeing new to perl and not wanting to learn using it like assembler, I
:) need to delete parts of a single line (possibly long) that are enclosed
:) between nested brackets:
:)
:) abcd efgh [ij: 123-[456]-klm; nop-789]; qrst; uvw [xyz: 98-76-[ef]; gh;
:) ijkl] (mnop)
:)
:) The comments between [] must be discarded to split with ';' delimiter.
:) The expected result is:
:) array[0] == "abcd efgh"
:) array[1] == "qrst"
:) array[2] == "uvw (mnop)"
:)
:) Thanks for a magic formula.
The magic formula is: \s*(\[[^][]*+(?:(?1)[^][]*+)*\])
my $_ = "abcd efgh [ij: 123-[456]-klm; nop-789]; qrst; uvw " .
"[xyz: 98-76-[ef]; gh;ijkl] (mnop)";
s {\s*(\[[^][]*+(?:(?1)[^][]*+)*\])} {}g;
my @array = split /;\s*/;
say qq {array[$_] == "}, $array [$_], qq {"} for 0 .. $#array;
__END__
array[0] == "abcd efgh"
array[1] == "qrst"
array[2] == "uvw (mnop)"
Abigail
--
perl -we 'print split /(?=(.*))/s => "Just another Perl Hacker\n";'
Re: how to remove blocks between nested brackets
am 01.02.2008 00:14:52 von sopan.shewale
Hi,
People have already answered your question - i just thought of adding
value to the discussion.
Have a look at the articles:
[1]. http://blog.stevenlevithan.com/archives/regex-recursion
[2]. http://perl.plover.com/yak/regex/samples/slide083.html
This articles will help you to understand the solutions posted in this
discussion and give high level understanding about the problem.
Regards,
--sopan shewale
On Jan 31, 8:20 am, Abigail wrote:
> _
> Si (silicium_a...@rmony-p.ath.cx) wrote on VCCLXVI September MCMXCIII in
> :
> :) Beeing new to perl and not wanting to learn using it like assembler, I
> :) need to delete parts of a single line (possibly long) that are enclosed
> :) between nested brackets:
> :)
> :) abcd efgh [ij: 123-[456]-klm; nop-789]; qrst; uvw [xyz: 98-76-[ef]; gh;
> :) ijkl] (mnop)
> :)
> :) The comments between [] must be discarded to split with ';' delimiter.
> :) The expected result is:
> :) array[0] == "abcd efgh"
> :) array[1] == "qrst"
> :) array[2] == "uvw (mnop)"
> :)
> :) Thanks for a magic formula.
>
> The magic formula is: \s*(\[[^][]*+(?:(?1)[^][]*+)*\])
>
> my $_ = "abcd efgh [ij: 123-[456]-klm; nop-789]; qrst; uvw " .
> "[xyz: 98-76-[ef]; gh;ijkl] (mnop)";
>
> s {\s*(\[[^][]*+(?:(?1)[^][]*+)*\])} {}g;
>
> my @array = split /;\s*/;
>
> say qq {array[$_] == "}, $array [$_], qq {"} for 0 .. $#array;
>
> __END__
> array[0] == "abcd efgh"
> array[1] == "qrst"
> array[2] == "uvw (mnop)"
>
> Abigail
> --
> perl -we 'print split /(?=(.*))/s => "Just another Perl Hacker\n";'