array_filter problem with 0"s

I have a string
$num = "012 4290-2008";
I made it an array with

I tried to get the integers from the string like this.

$value = str_split($num);
$value_new = array_filter($value, "return_int");

function return_int($value){
if(ctype_digit($value)){
echo $value;
return $value;
}
}

The echo prints out all the digits including the 0.
But the $value_new are missing the 0's.
I would appreciate it if some one can point me in the right direction

Thanks in advance

Chris


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Re: array_filter problem with 0"s

Hi Chris,

You need to return true or false from "return_int" function.
As "0" will be treated as false it will not be returned to filtered
result array.

Change the function "return_int" like below, then you should be able
to get proper array.

function return_int($value){
if(ctype_digit($value)){
echo $value."\t";
return true;
}else{
return false;
}
}

Thanks,
Sanjay Mantoor

On Wed, Jul 23, 2008 at 2:31 PM, Chris wrote:
> I have a string
> $num = "012 4290-2008";
> I made it an array with
>
> I tried to get the integers from the string like this.
>
> $value = str_split($num);
> $value_new = array_filter($value, "return_int");
>
> function return_int($value){
> if(ctype_digit($value)){
> echo $value;
> return $value;
> }
> }
>
> The echo prints out all the digits including the 0.
> But the $value_new are missing the 0's.
> I would appreciate it if some one can point me in the right direction
>
> Thanks in advance
>
> Chris
>
>
> --
> PHP Database Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>



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Thanks,
Sanjay Mantoor

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