Re: isset not functioning -RESOLVED
am 03.08.2009 19:19:53 von Allen McCabe--0016361e812c70455f04703ffa18
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Thanks!
On Mon, Aug 3, 2009 at 10:13 AM, Andrew Ballard
> On Mon, Aug 3, 2009 at 1:08 PM, Allen McCabe
> wrote:
> > I created a simple survey for my work website, most of the PHP is on my
> > process.php document, which is referenced by a form on a seperate page
> > containing the form with the method of "post".
> >
> > On my process.php page, the script obtains the field data using the
> > $_REQUEST[] function.
> >
> > I have a small if statement to check to see if they filled out the
> > 'firstname' field, and if they did not, to replace $name with "Sir or
> > Madam". Unfortunately, $name always equals "Sir or Madam", wether a value
> > for "firstname" was entered or not.
> >
> > All the of the other instances of using $_REQUEST[] functions just fine,
> but
> > don't make use of if or isset. Here is the code snippet:
> >
> > if(isset($_REQUEST['firstname']) && !empty($RESULT['firstname'])) {
> > $name = $_REQUEST['firstname'];
> > } else {
> > $name = 'Sir or Madam';
> > }
> >
> > I also tried adding an underscore to $RESULT (I got the code for this
> from a
> > php.net comment on the manual), to make it $_RESULT, but this doesn't
> seem
> > to be a pre-set function, and it still does not make it work. I am
> guessing
> > the user neglected to define $RESULT in his snippet, or I overlooked it.
> >
> > Can anyone see any problems with the code?
> >
>
> You are switching from $_REQUEST to $RESULT. Trying to use $_RESULT
> won't make it any better.
>
> Andrew
>
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