Logic of conditionals and the ( ) operators

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In a nutshell:

Will this work?

if ($perm == (11 || 12))


Explanation:

I am laying the groundwork for a photo viewing system with a private and
public mode, and additionally if an admin is logged in, there is an
additional level of permission. I came up with a number system to make it
easier (and is calcualted by a class) so now, instead of checking against
the $mode variable, if the user is logged in, and then what their user level
is if they are logged in, I just check against some numbers (the class
evaluates all those conditions and assigns the appropriate number a single
permission variable, $perm.

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Re: Logic of conditionals and the ( ) operators

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On Fri, 2009-12-18 at 10:21 -0800, Allen McCabe wrote:

> In a nutshell:
>
> Will this work?
>
> if ($perm == (11 || 12))
>
>
> Explanation:
>
> I am laying the groundwork for a photo viewing system with a private and
> public mode, and additionally if an admin is logged in, there is an
> additional level of permission. I came up with a number system to make it
> easier (and is calcualted by a class) so now, instead of checking against
> the $mode variable, if the user is logged in, and then what their user level
> is if they are logged in, I just check against some numbers (the class
> evaluates all those conditions and assigns the appropriate number a single
> permission variable, $perm.


That equates to if($perm == true) as 11 in this case translates to true
(being a positive integer) The code never needs to figure out the ||
part, as the first part is true.

I think what you'd want to do is possibly:

if($perm == 11 || $perm == 12)

Thanks,
Ash
http://www.ashleysheridan.co.uk



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Re: Logic of conditionals and the ( ) operators

Hi,

Yes, what Ashley said is correct. Also, if you want to avoid writing
$perm several times in the if, or if you have a lot of permissions you
can do:

if (in_array($perm, array(11, 22)))

And you can put in that array all the permissions you need to.

Regards,

Jonathan

On Fri, Dec 18, 2009 at 3:47 PM, Ashley Sheridan
wrote:
> On Fri, 2009-12-18 at 10:21 -0800, Allen McCabe wrote:
>
>> In a nutshell:
>>
>> Will this work?
>>
>> if ($perm == (11 || 12))
>>
>>
>> Explanation:
>>
>> I am laying the groundwork for a photo viewing system with a private and
>> public mode, and additionally if an admin is logged in, there is an
>> additional level of permission. I came up with a number system to make it
>> easier (and is calcualted by a class) so now, instead of checking against
>> the $mode variable, if the user is logged in, and then what their user level
>> is if they are logged in, I just check against some numbers (the class
>> evaluates all those conditions and assigns the appropriate number a single
>> permission variable, $perm.
>
>
> That equates to if($perm == true) as 11 in this case translates to true
> (being a positive integer) The code never needs to figure out the ||
> part, as the first part is true.
>
> I think what you'd want to do is possibly:
>
> if($perm == 11 || $perm == 12)
>
> Thanks,
> Ash
> http://www.ashleysheridan.co.uk
>
>
>

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