Help me dig out of a mini-nightmare. Some parameters transfer, others do not.

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Along with suggestions from this group, I was able to transfer
parameters across html pages so that
a user could pick a wood species and the new page would faithfully
report details on that wood.
Later (with help from the group again) I was so glad to see that
these pages were able to pick up
JPEG scans of how some woods look like, one more important step
forward for the project. When I then added a form for users to choose
what extra data they wanted to see and it would recycle to
the same page, the scan picture would disappear. A suggestion of
adding a hidden field in the form
even fixed that :-) . Things went swimmingly for a while.

I don't know just what I did wrong but somewhere between trying to
add some Javascript to create
new pop ups (they even work now, too) for user choices for showing
other photos, I messed up the page bad enough that it took a few days
to even get everything showing up again. Well .... almost everything.

It is able to pick up the choice of botanical name that a user
chooses from a very large list of woods and display the text data for
that one wood just fine again on another page. What I cannot seem to
get back again is to show the wood scans for those woods for which I
have scans (.... literally scanned on a scanner, btw, instead of a camera).

I have temporarily hard coded a full path and file name for a typical
wood that should have a picture
to show .... and the scan shows up just great, proving that part of
the logic is still intact, fine and working. The problem seems to be
for some reason that I no longer understand in getting the name and
partial path of the scan file to show up via the super-globals.

Both the botanical name ('species_name') and the scan picture name
('picture_filename1')
are stored in the table 'species'. The scans actually have a gallery
folder as part of what is stored
(eg. "gallery_a/ablies_alba, gallery_b/betula_nigra, and so on).

I have tried using (parse_str($_SERVER['QUERY_STRING'], $qs). I have
tried using $_GET that
has worked well before ..... but to no avail. I did try experimenting
quite a bit before finally and
with some regret deciding I am past what I know on why NOW
(remembering this used to work)
I just cannot get the content from column picture_file1 to come
across also. I keep saying it SHOULD
work.... but it doesn't.

With more and more functions being installed on this page, I will
still put the whole page code,
even though it will have sections that need no attention ... just to
be on the cautious side. This seems
so elementary and yet I cannot get it to work. (bear with so many
commented statements .... stabs
at getting this to work).

Three steps forward ..... one step back ......

Bill Mudry

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parse_str($_SERVER['QUERY_STRING'], $qs);
$species_name=$qs['species_name'];

Echo "on line18 \$qs is - $qs
";

parse_str($_SERVER['QUERY_STRING'], $qs2);
$picture_filename1 = $qs2['picture_filename1'];

Echo "on line 21 \$picture_filename is - $picture_filename
";

//$picture_filename1=$qs['picture_filename1'];

//$picture_filename = $_GET['picture_filename'];

$species_commonname = $_GET['species_commonname'];

//echo "\$species_commonname value at line 24 is - $species_commonname
";



#
//////////////////////////////////////////////////////////// ////////////////////////
# CONNECT TO DATABASE
#
//////////////////////////////////////////////////////////// ////////////////////////


include ("connecttotaxa.php");
$connection = mysql_connect($hostname, $username, $password)
or die("Unable to connect to database server");

$db = mysql_select_db($dbname, $connection)
or die("Unable to connect to database");


/*
------------------------------------------------------------ --------------------
HOPEFULLY CONNECTED AT THIS POINT
------------------------------------------------------------ ----------------------

*/


$query6 = "SELECT * FROM species WHERE species_name='$species_name'";
//var_dump($query6);
$result6 = mysql_query($query6)
or die(mysql_error());


If ($result6)
{
$row6=mysql_fetch_array($result6, MYSQL_ASSOC);
Echo "\$row6 is - $row6
\n";
Echo MYSQL_ERROR();
};
/*
if ($row6){
$z=extract($row6); //Echo MYSQL_ERROR();
};
*/


?>






Echo "" ;
//Echo "";


?>