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hi,
i have following code.
$target = "abc,xyz";
print "$target\n";
$target =~ s/,/\s/g;
print "$target\n";
i need to replace "comma" with whitespace for string "abc,xyz"
the output shud be "abc xyz"
the above regular expression does not do that . please suggest
--irfan
--0-864565372-1303999512=:5396--
Irfan Sayed wrote:
> hi,
Hello,
> i have following code.
>
>
> $target = "abc,xyz";
> print "$target\n";
> $target =~ s/,/\s/g;
> print "$target\n";
>
> i need to replace "comma" with whitespace for string "abc,xyz"
"Whitespace" is something that applies only to regular expressions but
the second part of the substitution operator is just a string, not a
regular expression. And which of the five whitespace characters should
this string interpolate "\s" as: " ", "\r", "n", "t" or "\f"?
> the output shud be "abc xyz"
>
>
> the above regular expression does not do that . please suggest
$target =~ tr/,/ /;
John
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John W. Krahn wrote:
> Irfan Sayed wrote:
>
>> i have following code.
>>
>>
>> $target = "abc,xyz";
>> print "$target\n";
>> $target =~ s/,/\s/g;
>> print "$target\n";
>>
>> i need to replace "comma" with whitespace for string "abc,xyz"
>
> "Whitespace" is something that applies only to regular expressions but
> the second part of the substitution operator is just a string, not a
> regular expression. And which of the five whitespace characters should
> this string interpolate "\s" as: " ", "\r", "n", "t" or "\f"?
Should be: " ", "\r", "\n", "\t" or "\f"
John
--
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more complex... It takes a touch of genius -
and a lot of courage to move in the opposite
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On 11-04-28 10:05 AM, Irfan Sayed wrote:
> hi,
>
> i have following code.
>
>
> $target = "abc,xyz";
> print "$target\n";
> $target =~ s/,/\s/g;
> print "$target\n";
>
> i need to replace "comma" with whitespace for string "abc,xyz"
>
> the output shud be "abc xyz"
>
>
> the above regular expression does not do that . please suggest
>
>
> --irfan
The white space meta-character does not work on the replace side of a
substitution. Use a space character:
$target =~ s/\,/ /g;
Some people prefer to use the hexadecimal format because in some fonts,
it's hard to distinguish between // and / /. Having something visible
makes the meaning clear.
Like this:
$target =~ s/\,/\x20/g;
--
Just my 0.00000002 million dollars worth,
Shawn
Confusion is the first step of understanding.
Programming is as much about organization and communication
as it is about coding.
The secret to great software: Fail early & often.
Eliminate software piracy: use only FLOSS.
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--0-1933330801-1304000934=:50433
Content-Type: text/plain; charset=iso-8859-1
Content-Transfer-Encoding: quoted-printable
my logic was to just put the space character in place of comma and keep res=
t as it is
but unfortunately that does not work
thanks john for=
your trick
=0Ait is working now
=0A____________________________=
____=0AFrom: John W. Krahn
expression
Irfan Sayed wrote:=0A> hi,
Hello,
=0A> i have fo=
llowing code.=0A>=0A>=0A> $target =3D "abc,xyz";=0A> print "$target\n";=0A>=
$target =3D~ s/,/\s/g;=0A> print "$target\n";=0A>=0A> i need to replace "c=
omma" with whitespace for string "abc,xyz"
"Whitespace" is something t=
hat applies only to regular expressions but =0Athe second part of the subst=
itution operator is just a string, not a =0Aregular expression.=A0 And whic=
h of the five whitespace characters should =0Athis string interpolate "\s" =
as: " ", "\r", "n", "t" or "\f"?
=0A> the output shud be "abc xyz"=0A>=
=0A>=0A> the above regular expression does not do that . please suggest=0A=
=0A$target =3D~ tr/,/ /;
John=0A-- =0AAny intelligent fool can m=
ake things bigger and=0Amore complex... It takes a touch of genius -=0Aand =
a lot of courage to move in the opposite=0Adirection.=A0 =A0 =A0 =A0 =A0 =
=A0 =A0 =A0 =A0 -- Albert Einstein
-- =0ATo unsubscribe, e-mail: begi=
nners-unsubscribe@perl.org=0AFor additional commands, e-mail: beginners-hel=
p@perl.org=0Ahttp://learn.perl.org/
--0-1933330801-1304000934=:50433--
--0-58235633-1304001004=:25994
Content-Type: text/plain; charset=iso-8859-1
Content-Transfer-Encoding: quoted-printable
thanks all
________________________________=0AFrom: Shawn H Core=
y
2011 7:55 PM=0ASubject: Re: regular expression
On 11-04-28 10:05 AM, =
Irfan Sayed wrote:=0A> hi,=0A>=0A> i have following code.=0A>=0A>=0A> $targ=
et =3D "abc,xyz";=0A> print "$target\n";=0A> $target =3D~ s/,/\s/g;=0A> pri=
nt "$target\n";=0A>=0A> i need to replace "comma" with whitespace for strin=
g "abc,xyz"=0A>=0A> the output shud be "abc xyz"=0A>=0A>=0A> the above regu=
lar expression does not do that . please suggest=0A>=0A>=0A> --irfan
T=
he white space meta-character does not work on the replace side of a =0Asub=
stitution.=A0 Use a space character:
$target =3D~ s/\,/ /g;
Some =
people prefer to use the hexadecimal format because in some fonts, =0Ait's =
hard to distinguish between // and / /.=A0 Having something visible =0Amake=
s the meaning clear.
Like this:
$target =3D~ s/\,/\x20/g;
=
=0A-- =0AJust my 0.00000002 million dollars worth,
Shawn
Confus=
ion is the first step of understanding.
Programming is as much about o=
rganization and communication=0Aas it is about coding.
The secret to g=
reat software:=A0 Fail early & often.
Eliminate software piracy:=A0 us=
e only FLOSS.
-- =0ATo unsubscribe, e-mail: beginners-unsubscribe@perl=
..org=0AFor additional commands, e-mail: beginners-help@perl.org=0Ahttp://le=
arn.perl.org/
--0-58235633-1304001004=:25994--
----- Original Message -----
From: "Irfan Sayed"
To: "John W. Krahn"
Sent: Thursday, April 28, 2011 9:28 AM
Subject: Re: regular expression
>
> my logic was to just put the space character in place of comma and keep
> rest as it is
>
> but unfortunately that does not work
Well, to be precise, your conceptual logic was fine; the implementation was
flawed. As several have pointed out, you weren't replacing the comma with a
_space_ *character*, but with the RegExp _whitespace_ *character class*.
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>>>>> "KK" == Karl Kaufman
KK> Well, to be precise, your conceptual logic was fine; the
KK> implementation was flawed. As several have pointed out, you
KK> weren't replacing the comma with a _space_ *character*, but with
KK> the RegExp _whitespace_ *character class*.
to be really precise, there was no character class in that code.
he was replacing the comma with the letter s. the right side of s///
is normally just a double quoted string and \s becomes just an s. this
shows it:
perl -le '$x = "a,b" ; $x =~ s/,/\s/; print $x'
asb
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